What were the limition of doberiner classifacation
1 answer:
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Answer : The energy removed must be, -67.7 kJ
Solution :
The process involved in this problem are :
The expression used will be:
where,
= heat released by the reaction = ?
m = mass of benzene = 125 g
= specific heat of gaseous benzene =
= specific heat of liquid benzene =
= enthalpy change for vaporization =
Molar mass of benzene = 78.11 g/mole
Now put all the given values in the above expression, we get:
Therefore, the energy removed must be, -67.7 kJ
The mass number represents the summation of the number of protons and the number of neutrons in the nucleus of an atom.
We are given that the mass number is 64 and that the number of neutrons is 35. Therefore:
number of protons = 64 - 35 = 29 protons
In ground state, number of protons in an atom is equal to the number of electrons. Therefore,
number of electrons = 29 electron
Using the periodic table, we will find that the element that has 29 electrons in ground state is copper.
The nuclide symbol of copper is shown in the attached image.
We are given that the mass number is 64 and that the number of neutrons is 35. Therefore:
number of protons = 64 - 35 = 29 protons
In ground state, number of protons in an atom is equal to the number of electrons. Therefore,
number of electrons = 29 electron
Using the periodic table, we will find that the element that has 29 electrons in ground state is copper.
The nuclide symbol of copper is shown in the attached image.