What were the limition of doberiner classifacation

Data for CH3COOH(l) + C2H5OH(l) CH3COOC2H5(l) + H2O(l) balance were obtained at 100. The initial concentrations of the reagents

Sphinxa [80]

Answer:

Kc = 3.94

Explanation:

CH₃COOH(g) + C₂H₅OH(g) → CH₃COOC₂H₅(g) + H₂O(g)

Liquids aren't included in the equilibrium constant, but at 100°C, all four compounds are a gas. So the equilibrium equation is:

Kc = [CH₃COOC₂H₅] [H₂O] / ([CH₃COOH] [C₂H₅OH])

Set up an ICE table for each row and calculate the value of Kc. Then average the results. (See picture.)

Kc ≈ (3.919 + 4.012 + 3.902) / 3

Kc ≈ 3.94

3 0

3 years ago

PLEAS HURRY IM TIMED If something moves around and takes the shape of the container it is in, it is most likely a

den301095 [7]

Gas and liquid both take the shape of their container. The difference is gas molecules equally fills the space. Is there any more information?

7 0

3 years ago

Read 2 more answers

The order of elements in the periodic table is based on of elements in the periodic table is based on

Serhud [2]

The increasing atomic number

6 0

3 years ago

Read 2 more answers

If 125 cal are added to 56,0 g of solid iron, what is the change in temperature of the iron? The specific heat of iron

stealth61 [152]

There is the internet

4 0

2 years ago

Which of the following isoelectronic series is correctly ranked from largest ionic radius to smallest ionic radius? 1. N 3−, O 2

love history [14]

Answer:

Option 1: N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²

Explanation:

Ionic radius is the radius of an atom´s ion in ionic crystal structure. In an ion that lose an electron, to form a cation, the radius of the ion gets smaller, because the repulsion between electrons decrease because fewer electrons are present. Conversely, adding on electron to a neutral atom, to form an anion, causes electron - electron repulsions to increase, so the size of the radius of the ion gets bigger.

Isoelectronic species are ions or elements that have the same number of electrons in their electronic shells but have different overall charges, because of their different atomic numbers.

In a isolelectronic series (same number of electrons), the increase of the positive charge (given by the number of protons in the nucleus), will cause a decrease in radius beacuse the greater electrostatic attraction between the electrons and the nucleus. Consequently, the ion with the greatest nuclear charge will have the smallest ionic radius and the ion with the smallest nulear charge will have the largest ionic radius.

We will use this principle to solve our problem.

In our case, the given ions are:

N⁻³ : Z = 7, e⁻ = 10
O⁻²: Z= 8, e⁻ =10
F⁻: Z = 9, e⁻ = 10
Na⁺: Z= 11, e⁻ = 10
Mg⁺²: Z=12, e⁻ =10

where Z= number of protons, and e⁻ = number of electrons.

Hence the decreasing order of ionic radius is:

N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²

Have a nice day!

4 0

3 years ago

What were the limition of doberiner classifacation​

What were the limition of doberiner classifacation