3 years ago

What were the limition of doberiner classifacation

Chemistry

1 answer:

alexgriva [62]3 years ago

5 0

Answer: I don’t kno

Explanation:

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A certain weak acid, HA, has a Ka value of 2.6×10−7. Calculate the percent ionization of HA in a 0.10 M solution.

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The percent ionization is 0,16%

Explanation:

The percent ionization is defined as the number of ions that exist in a substance.

$PI=\frac{[A-]}{[HA]} x100$

First, we find the [A-] using the ka equation

HA ⇄ $H^{+} + A^{-}$

[H+] = [A-]

$Ka=\frac{[H+][A-]}{[HA]}\\ \\$

since the ionization constant is very small we can assume that the final concentration of [HA] is the same

$Ka=\frac{[H+]^{2} }{[HA]} \\\\$

$[H+]=\sqrt[2]{Ka.[HA]} \\\\$

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Now we calculate the percent ionization using these values

$PI=\frac{1,61210^{-4} }{0,1} X100$

PI=0,16%

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3 years ago

What were the limition of doberiner classifacation​

What were the limition of doberiner classifacation