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maw [93]
3 years ago
13

Which of the following is an example of behavioral variation?

Chemistry
1 answer:
ANTONII [103]3 years ago
5 0

Answer: A, parrots eat seeds, fruit, and nuts, while hawks eat meat.

Explanation:

This option is more onto the behavioral and what the parrots did, while the other options were more on the parrots physical attributions.

<em>I hope this helped! :)</em>

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How does ground water become polluted
solniwko [45]

Ground Water can become polluted from when fossils and things make their way to the bottom of the ground and polluted the ground water

3 0
2 years ago
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HHHAAAAALLLPPPP<br><br> It’s due tomorrow
iris [78.8K]

Answer:

D.

Explanation:

Only 0.0035% of the electromagnetic spectrum is visible to the human eye

Hopefully this helped :)

7 0
2 years ago
Hydrogen is unique among the elements because __________. 1. It has only one valence electron. 2. It is the only element that ca
Talja [164]

Answer:

3,4

Explanation:

Hydrogen has no other electron hence there is no screening of the valence electron by inner electrons. It is the lightest known element with a relative molecular mass of 2. Screening effect refers to the fact that inner or core electrons prevent the outermost electron from feeling the attractive force of the nucleus.

6 0
3 years ago
A 33.0 mL sample of 1.15 M KBr and a 59.0 mL sample of 0.660 M KBr are mixed. The solution is then heated to evaporate water unt
Oksi-84 [34.3K]

Answer:

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

Explanation:

<u>Step 1:</u> Data given

Sample 1: The 1.15 M sample  has a volume of 33.O mL

Sample 2: The 0.660 M sample has a volume of 59.0 mL

Molar mass of KBr = 119 g/mol

Molar mass of AgNO3 = 169.87 g/mol

<u>Step 2:</u> Calculate number of moles for both samples

Number of moles = Molarity * Volume

Sample 1:  1.15 M * 33 *10^-3 L = 0.03795 moles

Sample 2: 0.660 M *59*10^-3 L = 0.03894 moles

Total mol KBr = 0.03795 + 0.03894 = 0.07689 moles

<u>Step 3:</u> Calculate total mass

mass = Number of moles * Molar mass

mass = 0.07689 moles * 119 g/moles = 9.15 grams  ( in 55mL)

<u>Step 4</u>: Calculate moles of AgBr

AgNO3 reacts with KBr  

KBr(aq) + AgNO3(aq) → AgBr(s) + KNO3(aq)

1 mole of KBr consumed, needs 1 mole of AgNO3 to produce 1 mole of AgBr and 1 mole of KNO3

So 0.07689 moles of KBr wll need 0.07689 moles of AgNO3

<u>Step 5:</u> Calculate mass of silver nitrate

mass of AgNO3 = Moles of AgNO3 * Molar mass of AgNO3

mass of AgNO3 = 0.07689 moles * 169.87 g/mol = 13.06 grams

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

8 0
3 years ago
A sample of phosphorus-32 has a half-life of 14.28 days. If 55 g of this radioisotope remain unchanged after approximately 57 da
Flura [38]
55= No (1/2)^55/57
55= No (1/2)^3.9
55= No (1/2)^4
55= No (1/16)
No= 880 g
7 0
2 years ago
Read 2 more answers
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