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Sholpan [36]
3 years ago
8

Which statement about stars is correct?

Chemistry
1 answer:
denis23 [38]3 years ago
4 0

Answer:

A. star formation begins in a nebula.

Explanation:

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For each pair of terms below, write a sentence that summarizes how they are different.
lesantik [10]
Yyyyyyyyyyyyyyuuyyubvc
5 0
3 years ago
Mechanically weathered rock is broken down into smaller _________________________. (four word phrase)
scoundrel [369]
Weathering because Weathering<span> is the process where </span>rock<span> is dissolved, worn away or </span>broken down into smaller<span> and </span>smaller<span> pieces. There are </span>mechanical<span>, chemical and organic </span>weathering<span>processes. Organic </span>weathering<span> happens when plants </span>break<span> up </span>rocks<span> with their growing roots or plant acids help dissolve </span>rock<span>.</span>
5 0
3 years ago
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Dissolving potassium chlorate (KClO3) is even more endothermic than potassium chloride.
zhenek [66]

Answer:

The mass of KClO₃ that will absorb the same heat as 5 g of KCl is 3.424 g

Explanation:

Here we have

Heat of solution of KClO₃ = + 41.38 kJ/mol.

Heat of solution of KCl (+17.24 kJ/mol)

Therefore, 1 mole of KCl absorbs +17.24 kJ during dissolution

Molar mass of KCl = 74.5513 g/mol

Molar mass of KClO₃ = 122.55 g/mol

74.5513 g of KCl absorbs +17.24 kJ during dissolution, therefore, 5 g will absorb

\frac{17.24}{74.5513 } \times 5 \, \, kJ \, or  \, 1.156  \, kJ

Therefore the amount of KClO₃ to be dissolved to absorb 1.156 kJ of energy is given by

122.55 g of KClO₃ absorbs + 41.38 kJ, therefore,

\frac{1.156}{41.38} \times 122.55 \,  g = 3.424 \, g

Therefore the mass of KClO₃ that will absorb the same heat as 5 g of KCl = 3.424 g.

5 0
3 years ago
Which statement about gases is true
ExtremeBDS [4]
Umm well its particles are always moving and excited so they are not so close 
7 0
3 years ago
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The explosion of fuel in an automobile engine cylinder is an example of to energy.
Anon25 [30]
Yes its Chemical Energy released in the form of heat.
5 0
4 years ago
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