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2 years ago

11

What is the pH scale used for? a. Measures hydroxide ion concentration (strength of the acid or base) b. Measures hydronium ion

concentration (strength of the acid or base)

1 answer:

Talja [164]2 years ago

7 0

The correct answer is a. Measures hydroxide ion concentration (strength of the acid or base) because when you look at the scientific definition of the use of a PH scale it says... "Acidity is the amount of hydrogen protons present in a solution and basicity is the amount of hydroxide ions present in a solution. The pH scale measures how acidic or basic a substance is. It ranges from 0 to 14. A pH of 7 is neutral."

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how does electromagnetism effect the function of a generator (using magnetism to produce electrical energy)

Sati [7]

Explanation:

We know that a changing magnetic field induces a current in a conductor. For that reason a generator basically consist an element that produces a magnetic field that changes over time and a conductor where the current will be induced.

This element that produces a magnetic field can be one of the following:

- A permanent magnet: Which is basically like a regular magnet. The magnetic field that a permanent magnet produces does not change over time, we need a motor or any other external force to move the axis of the generator and cause the magnetic field to change.

- An electro-magnet. Which is basically a DC current flowing through a conductor. Basically, when current flows through a conductor it behaves exactly like a magnet. So what we commonly do, is to connect a conductor to a DC battery, and it will create a magnetic field.

Like we are using a DC battery to create a magnetic field, then the magnetic field won't change over time either. So we still need an external force to move the axis of the generator to produce AC electricity.

4 0

3 years ago

When an object with a negative charge is moved from point A to point B through an external electrical field, it gains electrical

Sergio039 [100]

Explanation:

As per the problem,

$\Delta U = (V_{B} - V_{A})(-q) > 0$

When q > 0 then -q is a negative charge . Since, change in potential energy ( $\Delta U$ ) increases.

or, $(V_{A} - V_{B})q$ > 0

or, $V_{A} > V_{B}$

Therefore, both positive and negative charge will move from $V_{A}$ to $V_{B}$ and as $V_{B} < V_{A}$ so both of them move through a negative potential difference.

Thus, we can conclude that the true statements are as follows.

The positively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).

The negatively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).

4 0

2 years ago

What is the net force (including direction and magnitude) acting on the object on the above left?

Ber [7]

Answer:

Explanation:

the net force on the right left is 25 N and is directed upward

the net force on the left one is zero because 200N force act upward and 200N force act downward so both cancel each other and net force is zero

i hope this will help you

7 0

2 years ago

Write equations for both the electric and magnetic fields for an electromagnetic wave in the red part of the visible spectrum th

Strike441 [17]

Answer:

$E=3.5(8.98*10^{6}x-2.69*10^{15}t)$

$B=1.17*10^{-8}(8.98*10^{6}x-2.69*10^{15}t)$

Explanation:

The electric field equation of a electromagnetic wave is given by:

$E=E_{max}(kx-\omega t)$ (1)

E(max) is the maximun value of E, it means the amplitude of the wave.
k is the wave number
ω is the angular frequency

We know that the wave length is λ = 700 nm and the peak electric field magnitude of 3.5 V/m, this value is correspond a E(max).

By definition:

$k=\frac{2\pi}{\lambda}$

$k=8.98*10^{6} [rad/m]$

And the relation between λ and f is:

$c=\lambda f$

$f=\frac{c}{\lambda}$

$f=\frac{3*10^{8}}{700*10^{-9}}$

$f=4.28*10^{14}$

The angular frequency equation is:

$\omega=2\pi f$

$\omega=2\pi*4.28*10^{14}$

$\omega=2.69*10^{15} [rad/s]$

Therefore, the E equation, suing (1), will be:

$E=3.5(8.98*10^{6}x-2.69*10^{15}t)$ (2)

For the magnetic field we have the next equation:

$B=B_{max}(kx-\omega t)$ (3)

It is the same as E. Here we just need to find B(max).

We can use this equation:

$E_{max}=cB_{max}$

$B_{max}=\frac{E_{max}}{c}=\frac{3.5}{3*10^{8}}$

$B_{max}=1.17*10^{-8}T$

Putting this in (3), finally we will have:

$B=1.17*10^{-8}(8.98*10^{6}x-2.69*10^{15}t)$ (4)

I hope it helps you!

8 0

3 years ago

Please someone answer this ASAP❗️❗️‼️‼️

kogti [31]

Starting making jokes and rapping

5 0

3 years ago