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den301095 [7]
2 years ago
7

In the fishbowl, the glass, water, rocks, and plastic plants are in thermal equilibrium. This situation means the temperature of

the rocks is...​
Physics
1 answer:
Assoli18 [71]2 years ago
7 0
To cold which it throws off the equilibrium of the other things and sticks to it longer
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Which choice is the BEST source of PROTEIN?<br> 1 Meat<br> 2 Bread<br> 3 Rice<br> 4 Apples
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Answer: It's 1 meat.

Explanation: Meat is a protein, bread and rice are grains, Apples are fruit!

Your welcome

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Difference between rest and motion?
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Answer:

Rest and motion are relative terms. In simple terms, an object that changes its position is said to be in motion while the opposite action causes an object to be at rest.

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A ball is thrown straight up into the air with an initial speed of 8.0 m/s. How long does it take for the rocket to reach its hi
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A motorcycle and a police car are moving toward one another. The police car emits sound with a frequency of 523 Hz and has a spe
Firdavs [7]

To solve this problem it is necessary to apply the concepts related to Dopler's Law. Dopler describes the change in frequency of a wave in relation to that of an observer who is in motion relative to the Source of the Wave.

It can be described as

f = \frac{c\pm v_r}{c\pm v_s}f_0

c = Propagation speed of waves in the medium

v_r= Speed of the receiver relative to the medium

v_s= Speed of the source relative to the medium

f_0 =Frequency emited by the source

The sign depends on whether the receiver or the source approach or move away from each other.

Our values are given by,

v_s = 32.2m/s \rightarrow Velocity of car

v_r = 14.8 m/s \rightarrow velocity of motor

c = 343m/s \rightarrow Velocity of sound

f_0 = 523Hz \rightarrowFrequency emited by the source

Replacing we have that

f = \frac{c + v_r}{c - v_s}f_0

f = \frac{343 + 14.8}{343 - 32}(523)

f = 601.7Hz

Therefore the frequency that hear the motorcyclist is 601.7Hz

8 0
3 years ago
The distance between the objective and eyepiece lenses in a microscope is 19 cm . The objective lens has a focal length of 5.5 m
kramer

Answer:

The focal length of eyepiece is 3.68 cm.

Explanation:

Given that,

Distance = 19 cm

Focal length = 5.5 mm

Magnification = 200

Object distance = -25 cm

We need to calculate the focal length

Using formula of magnification

m=\dfrac{d}{f_{o}}+\dfrac{-25}{f_{0}f_{e}}

Put the value into the formula

f_{e}=\dfrac{19\times(-25)}{.55(-200-\dfrac{19}{.55})}

f_{e}=3.68\ cm

Hence, The focal length of eyepiece is 3.68 cm.

3 0
3 years ago
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