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marissa [1.9K]
3 years ago
11

Is it possible for the momentum of a system consisting of two carts on a low-friction track to be zero even if both carts are mo

ving?
Physics
1 answer:
choli [55]3 years ago
4 0

Answer:

Yes, if the two carts are moving into opposite directions

Explanation:

The total momentum of the system of two carts is given by:

p=m_1 v_1 + m_2 v_2

where

m1, m2 are the masses of the two carts

v1, v2 are the velocities of the two carts

Let's remind that v (the velocity) is a vector, so its sign depends on the direction in which the cart is moving.

We want to know if it is possible that the total momentum of the system can be zero, so it must be:

p=0\\m_1 v_1 + m_2 v_2 = 0\\m_1 v_1 = -m_2 v_2

From this equation, we see that this condition can only occur if v1 and v2 have opposite signs. Opposite signs mean opposite directions: therefore, the total momentum can be zero if the two carts are moving into opposite directions.

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1.33 m^3 of fluid flows out of a pipe in 24.5 s. the fluid leaves the pipe at 3.55 m/s. what is the area of the pipe. (unit=m^2)
Margaret [11]

Answer:

0.015meter^{2}

Explanation:

Total volume of water coming out = 1.33meter^{3}

Also volume = Cross sectional area*Length covered

Length covered = Velocity *time

                           =24.5*3.55

                           =86.97 meter

Let the cross sectional area be A.

1.33 = 86.97*A

A =0.015meter^{2}

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A baseball has mass 0.145 kg.
Vesnalui [34]

Answer:

a).p=15.67kg*m/s

b). F=7.83N

Explanation:

change in momentum is the subtraction from "after momentum" of the "before momentum"  as momentum is a vector quantity this is a vector subtraction.

initial momentum of ball

m1v1 = (0.145)(44.0) = 6.38 kg-m/s

after momentum

m1v2 = (0.145)(64.0) = 9.28 kg-m/s

since these momentums are 180° opposite one must be called negative so their difference

6.38+9.28= 15.67 kg-m/s

change in momentum = 15.67 kg-m/s ANS a1

Impulse = change in momenutm = 15.67 ANS a2

b)

Impulse =Favg*t

I=(2.00)Favg

Impulse from (a2) = 15.67  

Favg = 15.67/2.00 =

F= 7.83 N

3 0
4 years ago
Mework
S_A_V [24]

The force applied by the student is 75 N

Explanation:

We can solve this problem by using Newton's second law, which states that the  force applied on an object is equal to the product between the mass of the object and its acceleration:

F=ma

where

F is the force applied

m is the mass of the object

a is the acceleration

In this problem,

m = 50 kg

a=1.5 m/s^2

Substituting, we find the force applied by the student:

F=(50)(1.5)=75 N

Learn more about Newton's second law of motion:

brainly.com/question/3820012

#LearnwithBrainly

8 0
3 years ago
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