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marissa [1.9K]
3 years ago
11

Is it possible for the momentum of a system consisting of two carts on a low-friction track to be zero even if both carts are mo

ving?
Physics
1 answer:
choli [55]3 years ago
4 0

Answer:

Yes, if the two carts are moving into opposite directions

Explanation:

The total momentum of the system of two carts is given by:

p=m_1 v_1 + m_2 v_2

where

m1, m2 are the masses of the two carts

v1, v2 are the velocities of the two carts

Let's remind that v (the velocity) is a vector, so its sign depends on the direction in which the cart is moving.

We want to know if it is possible that the total momentum of the system can be zero, so it must be:

p=0\\m_1 v_1 + m_2 v_2 = 0\\m_1 v_1 = -m_2 v_2

From this equation, we see that this condition can only occur if v1 and v2 have opposite signs. Opposite signs mean opposite directions: therefore, the total momentum can be zero if the two carts are moving into opposite directions.

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A puck moves 2.35 m/s in a -22 degree direction. A hockey stick pushes it for 0.215 s, changing its velocity to 6.42 m/s in a 50
Whitepunk [10]

Answer:

Displacement in Y direction is 0.434 m

Explanation:

initial velocity of the puck is 2.35 m/s at -22 degree

so here it is given as

v_i = 2.35 cos22 \hat i - 2.35 sin22 \hat j

v_i = 2.18 \hat i - 0.88 \hat j

final velocity is given as 6.42 m/s at 50 degree

so we have

v_f = 6.42 cos50 \hat i + 6.42 sin50\hat j

v_f = 4.13 \hat i + 4.92\hat j

now displacement in Y direction is given as

\Delta y = \frac{v_f + v_i}{2}t

\Delta y = \frac{-0.88 + 4.92}{2} (0.215)

\Delta y = 0.434 m

5 0
3 years ago
A human services professional has worked with a particular client for a couple of years. The client
zhuklara [117]

Answer:

Respect the client’s decision

Explanation:

just took the test

4 0
2 years ago
A spherical balloon has a radius of 7.40 m and is filled with helium. Part A How large a cargo can it lift, assuming that the sk
malfutka [58]

Answer:

The mass of the cargo is M  =  188.43 \ kg

Explanation:

From the question we are told that

    The radius of the spherical balloon is  r =  7.40 \ m

     The mass of the balloon is  m = 990\ kg  

The volume of the spherical balloon is mathematically represented as

     V  =  \frac{4}{3} * \pi r^3

substituting values

      V  =  \frac{4}{3} * 3.142 *(7.40)^3

      V  =  1697.6 \ m^3

The total mass  the balloon can lift is mathematically represented as

     m =  V (\rho_h - \rho_a)

where \rho_h is the density of helium with a  value of

       \rho_h  =  0.179 \ kg /m^3

and  \rho_a is the density of air with a value of

        \rho_ a  = 1.29 \ kg / m^3

substituting values

          m =  1697.6 ( 1.29  - 0.179)

         m =  1886.0  \ kg

Now the mass of the cargo is mathematically evaluated as

        M  =  1886.0 - 1697.6

        M  =  188.43 \ kg

       

5 0
3 years ago
Find V. in the circuit of the following figure:​
Angelina_Jolie [31]

Answer:

where is the figure

Explanation:

8 0
3 years ago
Which of the following most logically completes the argument below?
kolezko [41]

Answer:

  (E) a greatly increased number of small particles in Earth’s orbit would result in a blanket of reflections that would make certain valuable telescope observations impossible

Explanation:

The trade is one strong reflection for many weak reflections (and more dangerous near-Earth space travel).

None of the answer choices except the last one has anything to do with the effect of exploding a satellite. When you are arguing that exploding a satellite is ill conceived, you need to address specifically the effects of exploding the satellite.

6 0
3 years ago
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