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bagirrra123 [75]
4 years ago
13

According to the Doppler Effect, which statement is true about a sound as it approaches you and then moves away.

Physics
2 answers:
Anarel [89]4 years ago
8 0

A) As the source approaches you, the sound waves are compressed so the pitch of the noise increases.

Fiesta28 [93]4 years ago
6 0
As the source approaches you, the sound waves are compressed, so
the pitch of the sound is higher than what the source is actually emitting.

Then, after it passes you and begins moving away, the sound waves
are stretched, so the pitch of the sound is lower than what the source
is actually emitting.
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Which nucleus completes the following equation?<br> A. 299 Np<br> B. 20Pa<br> C. 2 Pa<br> D. - Np
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Answer:

Option D. ²³⁹₉₃Np

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Let the unknown be ʸₓA.

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²³⁹₉₂U —> ⁰₋₁e + ʸₓA

Next, we shall determine the x, y and A. This can be obtained as follow:

92 = –1 + x

Collect like terms

92 + 1 = x

93 = x

x = 93

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239 = y

y = 239

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Thus, the complete equation is:

²³⁹₉₂U —> ⁰₋₁e + ²³⁹₉₃Np

7 0
3 years ago
The closest distance a book can be read from a pair of reading eyeglasses (Power = 1.55 dp) is 26.0 cm. What is the near distanc
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The image distance is 20.0 cm.

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f = \dfrac{1}{P}

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\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{-u}

Put the value into the formula

\dfrac{1}{v}=\dfrac{1}{64.5}-\dfrac{1}{-29}

\dfrac{1}{v}=\dfrac{187}{3741}

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Hence, The image distance is 20.0 cm.

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What is the magnification of an astronomical telescope whose objective lens has a focal length of 74 cm and whose eyepiece has a
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Answer:

The magnification of an astronomical telescope is -30.83.

Explanation:

The expression for the magnification of an astronomical telescope is as follows;

M=-\frac{f_o}{f_e}

Here, M is the magnification of an astronomical telescope, f_e is the focal length of the eyepiece lens and f_o is the focal length of the objective lens.

It is given in the problem that an astronomical telescope having a focal length of objective lens 74 cm and whose eyepiece has a focal length of 2.4 cm.

Put f_o=74 cm and f_e=2.4 cm in the above expression.

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Therefore, the magnification of an astronomical telescope is -30.83.

5 0
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