<u>Answer:</u> The mass percent of lead in lead (IV) carbonate is 63.32 %
<u>Explanation:</u>
The given chemical formula of lead (IV) carbonate is
To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:
Mass of lead = (1 × 207.2) = 207.2 g
Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g
Putting values in above equation, we get:
Hence, the mass percent of lead in lead (IV) carbonate is 63.32 %
Answer:
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Explanation:
It is clear that certain substituted benzene compounds reacts faster than benzene during electrophillic substitution reactions. This owes to the activation of the benzene ring towards electrophillic substitution by resonance.
The -OCH3 group is ortho- para directing hence it directs an incoming electrophile (such as during bromination) to the ortho or para position as shown in the image attached. This occurs due to resonance (mesomeric) effect as shown in the image attached to this answer.
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Answers are:
1) O₂ - linear.
2) CH₄ - tetrahedral.
3) SO₃ - t<span>rigonal planar.
4) SF</span>₄ - <span>trigonal bipyramidal.
5) BeF</span>₂ - linear.
6) SiCl₄ - <span>tetrahedral.
7) ClF</span>₃ - <span>T-shaped.</span><span>
8) CO</span>₂ - linear.
9) NH₃ - <span>trigonal pyramidal.
10) SO</span>₂ - bent.
11) H₃O⁺ - <span>trigonal pyramidal.
12) XeF</span>₄ - <span>square planar.
13) H</span>₂O - bent.
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Answer:
The trick here is to realize that the nitride anion, N3− , is isoelectronic with neon, Ne , the noble gas that shares a period with nitrogen, N . In other words, the nitride anion has the same number of electrons as neon.J
Explanation: