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Whitepunk [10]
3 years ago
8

Why does opening the air valve of a tire at a constant temperature decrease the pressure

Chemistry
1 answer:
Shtirlitz [24]3 years ago
8 0
The number of molecules decrease
You might be interested in
Oxidation unit test
3241004551 [841]

In this case, according to the given information about the oxidation numbers anf the compounds given, it turns out possible to figure out the oxidation number of manganese in both MnI2, manganese (II) iodide and MnO2, manganese (IV) oxide, by using the concept of charge balance.

Thus, we can define the oxidation state of iodine and oxygen as -1 and -2, respectively, since the former needs one electron to complete the octet and the latter, two of them.

Next, we can write the following x, since manganese has five oxidation states, and it is necessary to calculate the appropriate ones:

Mn^xI_2^-\\\\Mn ^xO_2^{-2}

Next, we multiply each anion's oxidation number by the subscript, to obtain the following:

Mn^xI_2^-\rightarrow x-2=0;x=+2\\\\Mn ^xO_2^{-2}\rightarrow x-4=0;x=+4

Thus, the correct choice is Manganese has an oxidation number of +2 in Mnl2 and +4 in MnO2.

Learn more:

  • brainly.com/question/15167411
  • brainly.com/question/6710925
8 0
3 years ago
C3H8 and CH4 are 2 compounds made from the same elements. This is an example of which law? A) Law of Conservation of Mass b) Law
Sphinxa [80]

C3H8 and CH4 are two compounds made from the same two elements, C and H. The ratios of C and H for both are round numbers.

Law of multiple proportions states that when two elements combine with each other to form more than one compound, the weights of one element that combine with a fixed weight of the other are in a ratio of small whole numbers.

So the ans is C) Law of Multiple Proportions

6 0
3 years ago
Helium and nickel are examples of ________. These
emmasim [6.3K]

Answer:

Elements, in turn, are pure substances—such as nickel, hydrogen, and helium—that make up all kinds of matter.

Hope This Helps!       Have A Nice Day!!

3 0
3 years ago
A gas at 928 kpa, 129 C occupies a volume of 569 L. Calculate the volume at 319 kpa and<br> 32 C.
lisabon 2012 [21]

Answer:

1255.4L

Explanation:

Given parameters:

P₁  = 928kpa

T₁  = 129°C

V₁  = 569L

P₂ = 319kpa

T₂  = 32°C

Unknown:

V₂  = ?

Solution:

The combined gas law application to this problem can help us solve it. It is mathematically expressed as;

           \frac{P_{1} V_{1} }{T_{1} }   = \frac{P_{2} V_{2} }{T_{2} }

P, V and T are pressure, volume and temperature

where 1 and 2 are initial and final states.

Now,

 take the units to the appropriate ones;

             kpa to atm,  °C to K

P₂ = 319kpa in atm gives 3.15atm

P₁  = 928kpa gives 9.16atm

T₂  = 32°C gives 273 + 32  = 305K

T₁  = 129°C gives 129 + 273  = 402K

Input the values in the equation and solve for V₂;

        \frac{9.16  x 569}{402}   = \frac{3.15 x V_{2} }{305}

       V₂   = 1255.4L

4 0
3 years ago
A silver coin with a mass of 14.1g has a density of 10.5 grams
Angelina_Jolie [31]

Answer:

1.34 cubic centimeter

Explanation:

v = m/d

5 0
3 years ago
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