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allochka39001 [22]
3 years ago
13

Why do the aquatic plants not break down by water current?

Chemistry
1 answer:
Lelechka [254]3 years ago
6 0
Leaves of aquatic plants are covered by a waxy cuticle which does not allow the water to wet them.
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Please help!!
prisoha [69]
A word equation is a written description of a chemical reaction.
All word equations start with the reactants.
Then, what comes next is the word "react to form."
Finally, the products of the equation are mentioned.
An example is,
Zinc and Hypochondriac acid react to form hydrogen gas and zinc chloride.
3 0
3 years ago
How many grams of lead(II) sulfate (303 g/mol) are needed to react with sodium chromate (162 g/mol) in order to produce 0.162 kg
Afina-wow [57]

Answer : The mass of PbSO_4 needed are, 1.515 grams.

Explanation :

First we have to calculate the mole of PbCrO_4.

\text{Moles of }PbCrO_4=\frac{\text{Mass of }PbCrO_4}{\text{Molar mass of }PbCrO_4}=\frac{0.162g}{323g/mole}=0.005mole

Now we have to calculate the moles of PbSO_4.

The balanced chemical reaction will be,

PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4 produced from 1 mole of PbSO_4

So, 0.005 mole of PbCrO_4 produced from 0.005 mole of PbSO_4

Now we have to calculate the mass of PbSO_4

\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4

\text{Mass of }PbSO_4=0.005mole\times 303g/mole=1.515g

Therefore, the mass of PbSO_4 needed are, 1.515 grams.

6 0
2 years ago
A large rift valley can be found along the east coast of Africa. It has been slowly widening over time, and it is now wide enoug
Serjik [45]

Answer:

wind and water erosion

4 0
3 years ago
Read 2 more answers
All the following are signs of a chemical reaction, except
hodyreva [135]
C. a change of state. It can be a physical or a chemical state of change.
8 0
2 years ago
Read 2 more answers
Someone please help me!! I'll give brainlest!
Trava [24]

Answer:

Section Three

1. D

2. B

3. A

4. G

5. C

6. F

7. E

Section Four

1. F

2. E

3. B

4. A

5. C

6. D

7. G

Explanation:

4 0
2 years ago
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