<u>Given:</u>
A → Products
[A] M Rate(M/s)
1. 0.15 0.014
2. 0.30 0.113
3. 0.60 0.905
<u>To determine:</u>
Order of the reaction
<u>Explanation:</u>
The rate of the given reaction can be expressed as:
Rate = k [A]ⁿ-----(1)
where k = rate constant
[A] = concentration of A
n = reaction order
Based on equation (1) the Rates 1 and 2 can be expressed as:
0.014 = k[0.15]ⁿ ------(3)
0.113 = k[0.30]ⁿ-------(4)
Dividing eq (4) by (3) we get:
0.113/0.014 = [0.30/0.15]ⁿ
8 = 2ⁿ
i.e. 2³ = 2ⁿ
n = 3
Ans: Thus, the order of the reaction is 3
Answer:
Pilot scale up
Explanation:
Preformulation studies are carried out on candidate drug molecules that show sufficient pharmacological promise in animal model(pharma approach).
It involves preliminary study of the properties of a drug which is considered a potentially active ingredient against a particular disease condition.
Scale-up is the term used to refer to the increase in the batch size of a product. This is only done after a drug has been proven successful against the target disease after extensive pilot studies.
Scale-up is the last operation carried out when a drug has passed through all stages. It is not included in preliminary preformulation studies
Answer:
isotopes
Explanation:
isotopes of the elements where the nucleas is unstable generally releases nuclear radiation.
Answer:
The molar concentration of Cu²⁺ in the initial solution is 6.964x10⁻⁴ M.
Explanation:
The first step to solving this problem is calculating the number of moles of Cu(NO₃)₂ added to the solution:
n = 1.375x10⁻⁵ mol
The second step is relating the number of moles to the signal. We know the the n calculated before is equivalent to a signal increase of 19.9 units (45.1-25.2):
1.375x10⁻⁵ mol _________ 19.9 units
x _________ 25.2 units
x = 1.741x10⁻⁵mol
Finally, we can calculate the Cu²⁺ concentration :
C = 1.741x10⁻⁵mol / 0.025 L
C = 6.964x10⁻⁴ M
Answer:
James Chadwick
Explanation:
In his first experiment, Rutherford was unable to predict the total mass of nucleus. He noticed that if only electrons and protons are present in the nucleus then by adding their masses, it falls short of the net mass of the atom. so he concluded that there must be another particle and that Particle was later discovered by James Chadwick in 1932.
