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xz_007 [3.2K]
3 years ago
10

Can yall pls help me with this, pls try to explain it in steps, ty!

Mathematics
2 answers:
inna [77]3 years ago
7 0

Answer: it MIGHT be c cuz it goes down FASST then slows down a bit on the loop the fast cuz its gong down and then slows a bit

Step-by-step explanation:

tatiyna3 years ago
6 0
<h3>Answer: Choice B (upper right corner)</h3>

==========================================================

Explanation:

At first the car isn't moving at all. This is at time 0. So this means the graph starts at the origin (0,0). Based on this alone, the answer is either choice B or choice C.

We can rule out choice C because the rates of change won't be constant to give those sharp straight lines. Instead, we have a gradual shift in speeds as the roller coaster progresses. So we'll have more of a curved shape as choice B shows.

Note that each time the car is going downhill, the speed goes up. On the flip side, as the car goes uphill, the speed goes down. So the direction of movement runs counter to the speed graph direction (one goes up, the other goes down).

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Bruce drew a scale drawing of a restaurant. The scale he used was 1 millimeter 10 meters The restaurant's kitchen is 3 millimete
Burka [1]

Answer:

answer=30

Step-by-step explanation:

by taking the length as x

1 millimetre = 10 metres

3 millimetres = x

10×3= 30 metres

HOPE THIS HELPS

8 0
2 years ago
g Annual starting salaries in a certain region of the U. S. for college graduates with an engineering major are normally distrib
algol13

Answer:

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that \mu = 39725, \sigma = 7320

Sample of 125

This means that n = 125, s = \frac{7320}{\sqrt{125}}

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{39000 - 39725}{\frac{7320}{\sqrt{125}}}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

1 - 0.1335 = 0.8665

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

4 0
2 years ago
Which statement matches the inequality − 2 &lt; 9?
swat32

Answer: Answer is C.

Step-by-step explanation: It is because positive numbers go to the right, and negative numbers to the left.

Hope that helps :)

8 0
2 years ago
Read 2 more answers
(-6+7) - (-4x - 2) ?
Law Incorporation [45]

the answer to your question is 7

6 0
3 years ago
Read 2 more answers
What is 5 1/4 . 1 5/9 ? Express the answer in simplest form
Agata [3.3K]
5\dfrac{1}{4}\cdot1\dfrac{5}{9}=\dfrac{5\cdot4+1}{4}\cdot\dfrac{1\cdot9+5}{9}=\dfrac{21}{4}\cdot\dfrac{14}{9}=\dfrac{7}{2}\cdot\dfrac{7}{3}\\\\=\dfrac{7\cdot7}{2\cdot3}=\dfrac{49}{6}=\dfrac{48+1}{6}=\boxed{8\dfrac{1}{6}}
8 0
3 years ago
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