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astraxan [27]
3 years ago
7

Please help :)

Chemistry
1 answer:
eimsori [14]3 years ago
6 0
Distance and period of time
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if 3.26 g of FeNO33 is dissolved in enough water to make exactly what is the molar concentration of nitrate ion g
Tanzania [10]

Answer:

0.404M

Explanation:

...<em>To make exactly 100.0mL of solution...</em>

Molar concentration is defined as the amount of moles of a solute (In this case, nitrate ion, NO₃⁻) in 1 L of solution.

To solve this question we need to convert the mass of Fe(NO₃)₃ to moles. As 1 mole of Fe(NO₃)₃ contains 3 moles of nitrate ion we can find moles of nitrate ion in 100.0mL of solution, and we can solve the amount of moles per liter:

<em>Moles Fe(NO₃)₃ -Molar mass: 241.86g/mol-:</em>

3.26g * (1mol / 241.86g) =

0.01348 moles Fe(NO₃)₃ * (3 moles of NO₃⁻ / 1mole Fe(NO₃)₃) =

<em>0.0404 moles of NO₃⁻</em>

In 100mL = 0.1L, the molar concentration is:

0.0404 moles of NO₃⁻ / 0.100L =

<h3>0.404M</h3>
5 0
2 years ago
1. What determines the reactivity of an atom?
Veronika [31]
The number of electrons in the outermost shell of an atom determines<span> its </span>reactivity<span>.</span><span>
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5 0
3 years ago
What type reaction is in the example below?<br><br>Na-Br + Cl-Cl --&gt; Na-Cl + Br-Br
Elis [28]

The type of reaction in the example below is a double replacement.

A double replacement can be identified by the switch between two reactants. This can be verified because both a Br and Cl are being switched to a new position in the reaction.  

8 0
3 years ago
Where are most algae found?
vladimir2022 [97]

Answer:

on the surface of lakes

Explanation:

8 0
3 years ago
Read 2 more answers
A 20.0 g sample of copper at 25.0 °c absorbs 475 j. What is the final temperature of the copper? (specific heat capacity of copp
maks197457 [2]

Given data:

Mass of copper (m)  = 20.0 g

Initial temperature of Copper (T1)=  25 C

Final temperature = T2

Heat absorbed by copper (Q) = 475 J

Specific heat of Copper (c) = 0.385 J/g C

Formula:

Q = mcΔT

   = mc(T2-T1)

475 = 20*0.385*(T2-25)

62.08 = T2-25

T2 = 87.08 = 87.1 C


8 0
3 years ago
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