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Serggg [28]
3 years ago
14

The reaction between iron(II) oxide and carbon monoxide produces iron and carbon dioxide. How many moles of iron can be obtained

when 1.50 mol FeO reacts with an excess of CO ?
FeO+CO⟶Fe+CO2
Chemistry
1 answer:
aleksandrvk [35]3 years ago
5 0

Answer:

1.5 moles of Fe produced.

Explanation:

Given data:

Moles of FeO react = 1.50 mol

Moles of iron produced = ?

Solution:

Chemical equation:

FeO + CO       →       Fe + CO₂

Now we will compare the moles of ironoxide with iron.

                           FeO          :           Fe

                              1             :             1

                             1.5           :           1.5

Thus from 1.5 moles of FeO 1.5 moles of Fe are produced.                                    

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<u>Answer:</u> The limiting reagent is oxygen gas.

<u>Explanation:</u>

Limiting reagent is defined as the reactant that is present in less amount and it limits the formation of products.

Excess reagent is defined as the reactant which is present in large amount.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

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Given mass of propane = 30.0 g

Molar mass of propane = 44.1 g/mol

Putting values in equation 1, we get:

\text{Moles of propane}=\frac{30.0g}{44.1g/mol}=0.680mol

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Putting values in equation 1, we get:

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By Stoichiometry of the reaction:

5 moles of oxygen gas reacts with 1 mole of propane.

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As, given amount of propane is more than the required amount. So, it is considered as an excess reagent.

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the molar mass is the mass of one mole of a substance.

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