Answer:
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Molar Mass of KCLO3
= 39 + 35.5 + 48 g
= 122.5 g .
So , percentage of Potassium ( K )
= 39 / 122.5 * 100 %
= 31.83 %
Now , percentage of Chlorine ( Cl )
= 35.5 / 122.5 * 100 %
= 28.97 %
So, finally, percentage of Oxygen ( O )
= 48 / 122.5 * 100 %
= 39.18 %
Hydrogen bonding, a particularly strong dipole-dipole force, causes a powerful attraction between water molecules, which results in a high boiling point.
Standard temperature and pressure (STP) means a temperature of 0°c and a pressure of 1 atmosphere (atm). The molar gas volume is used to convert between the number of moles of a gas and the volume of the gas at STP. One mole of a gas occupies a volume of 22400 cm³ or 22.4 liters at STP according to the molar gas volume.