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MArishka [77]
1 year ago
13

Five members of the computer club site to buy used computer dividing up the cost equally later three new members join a club of

the purchase price this result is a saving of $15 for each of the original five members what was the price of a used computer
Mathematics
1 answer:
BartSMP [9]1 year ago
7 0

The computation shows that the price of the used computer is $75.

<h3>How to compute the price?</h3>

From the information given, it should be noted that there are 5 members before the new members joined and $15 was given to each member.

Therefore, the price of the used computer will be:

= $15 × 5

= $75

The price of the used computer is $75.

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

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What is the value of the expression 5(X+3) when X=-3?
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Answer:

0

Step-by-step explanation:

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5(0)

0

4 0
3 years ago
Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

= w^{4} x^{2} y^{6} w^{9} x^{3}

3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
The heat developed in an electric wire varies jointly as the wires resistance, the time the current flows, &amp; the square of t
never [62]

Answer:

4 ohms

Step-by-step explanation:

The question is "In two minutes a current of 5 amps develops 1,200 heat units in a wire of 8 ohms resistance. What resistance does a similar wire have, which develops 6,000 heat units with a current of 10 amps in 5 minutes?"

Current, I₁ = 5 A

Heat, Q₁ = 1200 units

Resistance, R₁ = 8 ohms

Time, t₁ = 2 min = 120 s

New heat, Q₂ = 6000 units

Current, I₂ = 10 A

New time, t₂ = 5 min = 300 s

We need to find the new resistance.

Heat developed is given by :

Q=I^2Rt

\dfrac{Q_1}{I_1^2R_1t_1}=\dfrac{Q_2}{I_2^2R_2t_2}\\\\R_2=\dfrac{Q_2\times I_1^2R_1t_1}{Q_1I_2^2t_2}\\\\R_2=\dfrac{6000\times 5^2\times 8\times 120}{1200\times 10^2\times 300}\\\\=4\ \Omega

So, the new resistance is 4 ohms.

5 0
3 years ago
If x = -2, then the equation is 2x = -4.<br><br><br> True<br> or<br> False
Alex777 [14]

Answer:

true

Step-by-step explanation:

2(-2)=-4

6 0
3 years ago
An alloy of tin is 15% tin and weights 20 pounds. A second allow is 10% tin. How many pounds of the second alloy must be added t
Fofino [41]
Let x represent the amount to be added. The total amount of tin will be
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30 pounds of 10% tin must be added to get a 12% mixture.
8 0
3 years ago
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