Answer:
D) HCOOCH2CH3
Explanation:
An isomer of a compound is defined as a chemical substances with the same formula (That is, same atoms) but in different structures.
For propanoic acid, there are <em>3 atoms of C, 6 atoms of H and 2 atoms of oxygen.</em>
A) CH2CHCOOH
. Here you have 3 atoms of C but 4 atoms of H. That means this compound is not an isomer.
B) CH3CH2CH2COOH
. Here, there are 4 atoms of C. Thus, is not an isomer.
C) CH3CH(OH)CH2OH. This structure has 3 atoms of C, but 8 atoms of H. Thus, is not an isomer.
D) HCOOCH2CH3. Here, there are 3 atoms of C, 6 atoms of H and 2 atoms of O. Thus, this structure <em>is an isomer of propanoic acid.</em>
Answer:
3
Explanation:
2x5 is 10 then 13-10 is 3
Answer:
The correct answer is A)
Overtime, the finches on the island adapted as a result of competition for resources.
Explanation:
The finches beaks adapted to the food source which was favored by natural selection. The successful finches that had the most useful beak for their island survived and therefore reproduced.
Cheers!
The names of these constitutional isomers are cyclopentane, methylcyclobutane, ethylcyclopropane, and 1,1-dimethylcyclopropane.
Constitutional isomers have the same molecular formula. This means that they have the same number of carbon and hydrogen atoms, with a general formula of:
When we consider the possible structures, the first option is cyclopentane, the simplest five-membered ring. When we reduce the ring to four carbons, we have the methylcyclobutane and when we reduce it to three carbons, we can arrange the other two carbons in an ethyl group or we can put two methyl groups on a single carbon atom to get the final two constitutional isomers.
You can learn more about constitutional isomers here:
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The product for the following reaction are :
- 2 - butanone
- CH₃CH₂COCl
- CH₃CH₂CONHCH₃
T carboxylic acid is an organic compound. the functional group of carboxylic acid is carboxy. general formula is given as : R - COO⁻.
The reactions are given as follows :
1) the reduction of carboxylic acid into ketone with the organometallic compound is given as follows :
CH₃CH₂COOH + CH₃Li ------> CH₃CH₂COCH₃
2 butanone
2) the reaction of carboxylic acid with SOCl₂ is given as follows :
CH₃CH₂COOH + SOCl₂ -----> CH₃CH₂COCl
3) the reaction of carboxylic acid with CH₃NH₂ is given as follows
CH₃CH₂COOH + CH₃NH₂ -----> CH₃CH₂CONHCH₃
Thus, The product for the following reaction are :
- 2 - butanone
- CH₃CH₂COCl
- CH₃CH₂CONHCH₃
To learn more about carboxylic acid here
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