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My name is Ann [436]
3 years ago
8

What is the equilibrium equation for the dissociation of formic acid in water? hcooh (aq) + h2o (l) ⇌ h3o+ (aq) + hcoo- (aq)?

Chemistry
1 answer:
Pani-rosa [81]3 years ago
7 0
Formic acid when in water would dissociate into ions just like any acids. It would dissociate into the hydrogen ion and the formate ion. The equilibrium dissociation equation would be written as:

<span>HCOOH (aq) + H2O (l) ⇌ H+ (aq) + HCOO- (aq)

Formic acid is a weak acid which means that when in aqueous solution it does not completely dissociate into its corresponding ions. Only a certain amount that would be dissociated so in the solution there will be HCOOH, HCOO- and H+ molecules. It is also known as Methanoic acid and an important substance for the synthesis of a number of substances. It is naturally occurring in ants.</span>
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how many mL of a 3.5 M sodium hydroxide will be needed to neutralize 15mL of a 4.3 M hydrochloric acid solution?
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Step 1 : write a valanced equation..
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Step 2 : find the number of mole of HCl..
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Stem 3 : use mole ratio....
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Do the calculation
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