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AleksAgata [21]
3 years ago
13

Which species is the reducing agent in the reaction: 3ca (s) + 2cr3+ (aq) 2cr (s) + 3ca2+ (aq)?

Chemistry
1 answer:
k0ka [10]3 years ago
3 0
The redox reaction is as follows
3Ca + 2Cr³⁺ --> 3Ca²⁺ + 2Cr
in the oxidation reaction the species donates electrons and becomes oxidised.
the oxidised species donates electrons to the other species and reduces the other species hence its called the reducing agent as it reduces the other species. the oxidised species' oxidation number increases.
in the reduction reaction, the species takes in electrons and becomes electrons and its called the oxidising agent as it takes in electrons from the oxidised species thus oxidising the other species. the reduced species' oxidation number decreases.

in this case , Ca becomes oxidised
Ca --> Ca²⁺ + 2e
oxidation number of Ca increases from 0 to +2. since it reduces Cr from Cr³⁺ to Cr, Ca is called the reducing agent

hence answer is Ca, its the reducing agent 
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Calculate the molality for each of the following solutions. Then, calculate the freezing-point depression ΔTF = iKFcm produced b
zlopas [31]

Answer:

a) Cm= 3.9 m  ; ΔTf= 14.51 ºC

b) Cm= 0.21 m ; ΔTf= 0.79ºC

Explanation:

In order to solve the problems, we have to remember that the molality (m) of a solution is equal to moles of solute in 1 kg of solvent.

m= mol solute/kg solvent

a) In this case we have molarity, which is moles of solute in 1 liter of solution. We have to know how many kg of solvent (water) we have in 1 L of solution.

3.2 M NaCl= 3.2 mol NaCl/ 1 L solution

1 L solution= 1000 ml solution x 1.00 g/ml= 1000 g

A solution is composed by solute (NaCl) + solvent, so:

1000 g solution = g NaCl + g solvent

g NaCl= 3.2 mol NaCl x 58.44 g/mol= 187 g NaCl

g solvent= 1000 g - 187 g NaCl= 813 g= 0.813 kg

Cm= 3.2 g NaCl/0.813 kg solvent= 3.9 m

NaCl is an electrolyte and it dissociates in water in two ions: Na⁺ anc Cl⁻, si the van't Hoff factor (i) is 2.

ΔTf= i x KF x Cm= 2 x 1.86ºC/m x 3.9 m= 14.51ºC

b) In this case we have 24 g of solute in 1.5 L of solvent. We have to convert the liters of solvent to kg, and to convert the mass of solute to mol by using the molecular weight of KCl (74.55 g/mol):

24 g KCl x 1 mol KCl/74.55 g= 0.32 mol

1.5 L solvent= 1500 g solvent x 1.00 g/ml= 1500 g = 1.5 kg

Cm= 0.32 g KCl/1.5 kg solvent= 0.21 m

KCl is an electrolyte and when it dissolves in water, it dissociates in 2 ions: K⁺ and Cl⁻. For this, van't Hoff factor (i) is equal to 2.

ΔTf= i x KF x Cm= 2 x 1.86ºC x 0.21 m= 0.79ºC

7 0
3 years ago
A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 6.50kg of water at 24.2°C. Dur
sukhopar [10]

Answer:

27.4°C

Explanation:

Using the equation:

Q = m*C*T

<em>Where Q is heat added,</em>

<em>m the mass of water</em>

<em>C specific heat of water (4.18J/g°C)</em>

<em>And T the increase in temperature</em>

We can solve for the increase in temperature and thus, the final temperature of water:

Q = 88200J; m = 6500g:

88200J = 6500g*4.18J/g°C*T

3.2°C = T = increase in temperature

Final temperature is:

24.2°C + 3.2°C =

<h3>27.4°C</h3>
5 0
3 years ago
Crystalline solids melt at a specific temperature called the __________
natima [27]
Answer:Melting point
5 0
3 years ago
Read 2 more answers
A 1.00 liter container holds a mixture of 0.52 mg of He and 2.05 mg of Ne at 25oC. Determine the partial pressures of He and Ne
Ymorist [56]

Answer:

pHe = 3.2 × 10⁻³ atm

pNe = 2.5 × 10⁻³ atm

P = 5.7 × 10⁻³ atm

Explanation:

Given data

Volume = 1.00 L

Temperature = 25°C + 273 = 298 K

mHe = 0.52 mg = 0.52 × 10⁻³ g

mNe = 2.05 mg = 2.05 × 10⁻³ g

The molar mass of He is 4.00 g/mol. The moles of He are:

0.52 × 10⁻³ g × (1 mol / 4.00 g) = 1.3 × 10⁻⁴ mol

We can find the partial pressure of He using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.3 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 3.2 × 10⁻³ atm

The molar mass of Ne is 20.18 g/mol. The moles of Ne are:

2.05 × 10⁻³ g × (1 mol / 20.18 g) = 1.02 × 10⁻⁴ mol

We can find the partial pressure of Ne using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.02 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 2.5 × 10⁻³ atm

The total pressure is the sum of the partial pressures.

P = 3.2 × 10⁻³ atm + 2.5 × 10⁻³ atm = 5.7 × 10⁻³ atm

6 0
3 years ago
What is the mass in grams of 4.25 x 103moles of N2?
Dovator [93]
Mass =?
moles of N2 = 4.25 x 103 mol
molar mass of N2 = (14)x2 = 28
8 0
3 years ago
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