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Ivan
3 years ago
14

How much elastic potential energy is stored in a bungee cord with a spring constant of 10.0 N/m when the cord is stretched 2.00

m?
A. 10.0 J
B. 20.0 J
C. 40.0 J
D. 200 J
Physics
2 answers:
MrRissso [65]3 years ago
7 0

Elastic potential energy stored in bungee cord is 20.0 J.

Answer: Option B

<u>Explanation: </u>

The elastic potential energy is a form of potential energy stored in elastic materials. Generally potential energy is the energy of any object when it is at rest. But in materials possessing elastic properties, they store these potential energy in the form of elastic potential energy and it is used when the elastic materials undergoes elastic deformation.

For example, if we consider a spring, the elastic potential energy of the spring will be zero, when it is not deformed elastically i.e., when the spring is not stretched or compressed. But the same spring will be exhibiting elastic potential energy when the spring is stretched or compressed. So, the formula for elastic potential energy is

      \text { Elastic potential energy }=\frac{1}{2} \times \text { spring constant } \times\left(\frac{\text {stretching}}{\text {compressing distance}}\right)^{2}

In this case, as the spring constant of cord is given as 10 N/m and the stretching distance of the cord is given as 2 m, so the elastic potential energy stored in the cord will be

       \text { Elastic potential energy }=\frac{1}{2} \times 10 \times(2)^{2}=\frac{1}{2} \times 10 \times 4 = 20 J

UNO [17]3 years ago
5 0

the correct answer is B. 20.0 J

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3 years ago
A. The potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J. Find by
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a. The spring is compressed  by  0.174 m.

b.  The vertical distance the dart travels from its position when the spring is compressed to its highest position is 9.6 m.

c. The horizontal velocity of the dart at that time is  13.74 m/s.

d. The horizontal distance from the equilibrium position at which the dart hits the ground is 19.236 m.

<h3>What is potential energy?</h3>

The energy by virtue of its position is called the potential energy.

a. Given is the potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J.

PE  of spring = 1/2 kx²

Put the values, we get

P.E = 0.940 = 1/2 x 62 x²

x = 0.174 m

Thus, the spring is compressed by 0.174 m.

b. Given is a 0.010 kg dart is fired straight up.

The vertical height is find out by

0.940 J = (0.010 kg) (9.8 m/s²) h

h = 9.6 m

Thus, the vertical distance the dart travels from its position is 9.6 m

c. From the conservation of energy principle, total mechanical energy is conserved.

1/2 mv² =mgh

v = √2gh

Plug the values, we get

v = √2 x 9.8x 9.6

v = 13.74 m/s

Thus, the horizontal velocity is  13.74 m/s.

d.  Time that dart spends in air, t = √2h/g

t = √(2x9.6)/9.81

t = 1.4 s

The horizontal distance from the equilibrium position at which the dart hits the ground.

Horizontal distance = (Velocity on x direction) x time

Horizontal distance = 13.74 m/s x 1.4s

Horizontal distance = 19.236 m

Thus, the horizontal distance is 19.236 m.

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The frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.

<h3>What is a frequency?</h3>

The number of waves that travel through a particular point in a given length of time is described by frequency. So, if a wave takes half a second to pass, the frequency is 2 per second.

Given that the energy of the photon is 4.56 x 10⁻¹⁹ J. Therefore, the frequency of the photon can be written as,

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