Answer:
v = 6.72 m/s
Explanation:
Given that,
Vertical height, h = 2.31 m
We need to find the speed at the bottom of the slide. Let the speed be v. We can find it using the conservation of energy such that,
Put all the values,
So, her speed at the bottom of the slide is equal to 6.72 m/s.
Answer:
%Open the file.
fID = fopen('parts_inv.dat');
%Read from the file.
data = fscanf(fID,'%d\t%f\t%d',[3,inf]);
%Close
fclose(fID);
%Restore the data.
data = data';
%Get the size
[rs, cs] = size(data);
%Set value.
invCost = 0;
%Loop
for rw = 1 : rs
%Find cost
invCost = invCost + (data(rw, 2) * data(rw, 3));
%Loop end
end
%Display the cost.
fprintf('Total cost: %4.2f\n\n', invCost);
Explanation:
Answer:
Mater's Mass is the Answer
The one with the greatest mass would, when everything else is equal. I'm having trouble making out your list of choices.
On isolated ground receptacles, the metal yoke is not allowed to be integrally bonded to the equipment grounding terminal of the receptacle.
Any device with two distinct switches or receptacles is a duplex device. It can be shaped to fit a Decora opening or a typical duplex plate opening. It should be noted that they can be combination devices with a switch/outlet, switch/pilot light, etc.
Because of grounding connection removal and receptacle, it is utterly undesirable to connect the two bare equipment grounding conductors together directly.
The equipment grounding conductor associated with those circuits must be connected to the box when circuit conductors are terminated on equipment inside a metal box to prevent unneeded current discharge.
Learn more about grounding conductors here brainly.com/question/14886979
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