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Olenka [21]
3 years ago
14

Two planets, Dean and Sam, orbit the Sun. They each have with circular orbits, but orbit at different distances from the Sun. De

an orbits at a greater average distance than Sam. According to Kepler's Third Law, which planet will have a longer orbital period? Group of answer choices Dean Sam Since they both have circular orbits, they will have the same orbital periods. There isn't enough information to tell.
Physics
1 answer:
lyudmila [28]3 years ago
3 0

Answer:

The correct answer is Dean has a period greater than San

Explanation:

Kepler's third law is an application of Newton's second law where the force is the universal force of attraction for circular orbits, where it is obtained.

                T² = (4π² / G M)  r³

When applying this equation to our case, the planet with a greater orbit must have a greater period.

Consequently Dean must have a period greater than San which has the smallest orbit

The correct answer is Dean has a period greater than San

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The drill used by most dentists today is powered by a smallair-turbine that can operate at angular speeds of 350000{\rm rpm}. Th
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Answer:

α = 3070rev/s^2

θ = 5541.66 revolutions

Explanation:

Given;

Operating angular speed w = 350000 rpm

time t = 1.9s

Angular acceleration = change in angular speed/time

Angular acceleration=350000rpm×1/60 min/sec ÷ 1.9s

Angular acceleration α = 3070rev/s^2

Number of revolutions θ = 1/2 × α × t^2

Since initial angular speed is zero

Substituting the values;

θ = 1/2 × 3070 × 1.9^2

θ = 5541.66 revolutions

5 0
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An object has a mass of 2000kg what is its weight on earth
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Answer:

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Explanation:

weight = mass x gravity

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w = m x g

w = 2000 kg x 9.8 m/s^2

w = 19600 N

The weight of the object is 19600 N (newtons).

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