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Olenka [21]
2 years ago
14

Two planets, Dean and Sam, orbit the Sun. They each have with circular orbits, but orbit at different distances from the Sun. De

an orbits at a greater average distance than Sam. According to Kepler's Third Law, which planet will have a longer orbital period? Group of answer choices Dean Sam Since they both have circular orbits, they will have the same orbital periods. There isn't enough information to tell.
Physics
1 answer:
lyudmila [28]2 years ago
3 0

Answer:

The correct answer is Dean has a period greater than San

Explanation:

Kepler's third law is an application of Newton's second law where the force is the universal force of attraction for circular orbits, where it is obtained.

                T² = (4π² / G M)  r³

When applying this equation to our case, the planet with a greater orbit must have a greater period.

Consequently Dean must have a period greater than San which has the smallest orbit

The correct answer is Dean has a period greater than San

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prohojiy [21]

Answer:

The answer is 218

Explanation:

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weight is represented by F

F = 25kg (8.7)

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4 0
3 years ago
After a laser bean passes through two thin parallel slits, thefirst completely dark fringes occur at ± 15.00with the original di
PSYCHO15rus [73]

Answer:

143 °

Explanation:

a ) If d be the distance between slits , λ be wavelength of light used and at angle θ nth dark fringe is formed then

d sinθ = ( 2n+1) λ/2

for first dark fringe

d sinθ = λ/2

d /λ = 1/ 2 sinθ

1 / 2 sin15

= 1.93

b )

For intensity of fringe at angle θ,  the relation is

I = I₀ cos²θ

I / I₀  = cos²θ/2

Given I / I₀ =0. 1

0.1 = cos²θ/2

θ/2 = 71.5

θ = 143 °

4 0
2 years ago
On a trip you travel at a constant speed of 50 kilometers per hour North for 1 hour. Then you turn West and travel at a constant
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Answer:27 km per hour West + 17 km per hour North

6 0
2 years ago
Please correct answers only, if you don’t know, ignore. Please answer this or am I correct?
Wewaii [24]

Answer:

C is correct.

Explanation:

5 0
3 years ago
Read 2 more answers
Two carts undergo an inelastic collision where they stick together. Cart A has an initial velocity v0, and the second cart B is
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Answer:

Explanation:

Initial kinetic energy of the system = 1/2 mA v0²

If Vf be the final velocity of both the carts

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final velocity

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kinetic energy ( final ) =  1/2 (mA +mB)mA²vo² /  ( mA +mB)²

= mA²vo²  / 2( mA +mB)

Given 1/2 mA v0²  / mA²vo²  / 2( mA +mB) = 6

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mA + mB = 6 mA

5 mA = mB

mB / mA = 5 .

3 0
3 years ago
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