Answer:
value of fs,max under the circumstances is
f = 42.56 N
Explanation:
The formula is µ = f / N, where µ is the coefficient of friction, f is the amount of force that resists motion, and N is the normal force. Normal force is the force at which one surface is being pushed into another.
So f = µN
f = 0.380 * 112
f = 42.56 N
Answer:
B) 71.5 [km]
Explanation:
To solve this problem we will decompose each of the directions in the x & y axes.
To solve this problem we will decompose each of the directions in the x & y axes. also for a greater understanding of the angles, you should look at the attached image, which contains the orientations for each angle (clockwise or counterclockwise).
<u>59.0 km in a direction 30.0° east of north</u>
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![d_{1x}= 59*sin(30) = 29.5[km]\\d_{1y}= 59*cos(30) = 51.09[km]](https://tex.z-dn.net/?f=d_%7B1x%7D%3D%2059%2Asin%2830%29%20%3D%2029.5%5Bkm%5D%5C%5Cd_%7B1y%7D%3D%2059%2Acos%2830%29%20%3D%2051.09%5Bkm%5D)
<u>58.0 km due south</u>
<u />
![d_{2y} = - 58 [km]\\](https://tex.z-dn.net/?f=d_%7B2y%7D%20%3D%20-%2058%20%5Bkm%5D%5C%5C)
<u>It flies 100 km 30.0° north of west</u>
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Now we sum algebraically the components
![d_{x}=29.5-86.6 = -57.1[km]\\d_{y}=51.09 -58+50=43.09[km]\\\\](https://tex.z-dn.net/?f=d_%7Bx%7D%3D29.5-86.6%20%3D%20-57.1%5Bkm%5D%5C%5Cd_%7By%7D%3D51.09%20-58%2B50%3D43.09%5Bkm%5D%5C%5C%5C%5C)
Using the Pythagorean theorem we can find the magnitude of the displacement.
![d = \sqrt{(57.1)^{2} +(43.09)^{2} } \\d= 71.53[km]](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%2857.1%29%5E%7B2%7D%20%2B%2843.09%29%5E%7B2%7D%20%7D%20%5C%5Cd%3D%2071.53%5Bkm%5D)
Answer: Brownion motion is the erratic random movement of microscopic particles in a fluid, as a result of continuous bombardment from molecules of the surrounding medium.
Explanation:
Brownian motion is the random movement of particles in a fluid due to their collisions with other atoms or molecules.
depends t what stage in the fall it is. If it is at the peak, it is fully potential. If it is in the middle, it has both. If it is at the bottom of the fall, it is completely kinetic
The coefficient of static friction is 0.222
Explanation:
In order for the car to remain in circular motion, the frictional force must be able to provide the necessary centripetal force. Therefore, the car will start skidding when the two forces are equal:

where the term on the left is the frictional force, while the term on the right is the centripetal force, and where
is the coefficient of static friction
m is the mass of the car
g is the acceleration of gravity
v is the speed of the car
r is the radius of the track
In this problem, we have:
r = 564 m
v = 35 m/s

And re-arranging the equation for
, we can find the coefficient of static friction:

Learn more about friction:
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