Answer:
Part 1) Time of travel equals 61 seconds
Part 2) Maximum speed equals 39.66 m/s.
Explanation:
The final speed of the train when it completes half of it's journey is given by third equation of kinematics as
where
'v' is the final speed
'u' is initial speed
'a' is acceleration of the body
's' is the distance covered
Applying the given values we get
Now the time taken to attain the above velocity can be calculated by the first equation of kinematics as
Since the deceleration is same as acceleration hence the time to stop in the same distance shall be equal to the time taken to accelerate the first half of distance
Thus total time of journey equals
Part b)
the maximum speed is reached at the point when the train ends it's acceleration thus the maximum speed reached by the train equals 
Answer:
It includes earthwork, trenching, wall shafts, tunneling and underground
Explanation:
b..a harmless organism imitating the look of a harmful organism
Explanation:
A harmless organism imitating the look of a harmful organism is one example of mimicry that enables prey species avoid predation.
Prey are smaller and less harmful organisms often hunted by larger organisms usually carnivores.
Mimicry is a form of evolutionary adaptation process in which two organisms of the same specie or different species tends to look alike.
It is a subtle defense mechanism developed by organism over an extended period of time.
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Adaptation brainly.com/question/11105547
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The north vectors add up as so the south vectors. Then subtract the two. For north its 4 + 5 = 9. South is 2 + 5 = 7. Then 9-7 = 2km North (D)
