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3 years ago

10

Desde lo alto de un acantilado de 140 m, se lanza verticalmente un objeto hacia abajo con velocidad de 3m/s. Entonces la magnitu

d del desplazamiento que ejecuta en t = 3s es: (use g = 10 m/s2)

1 answer:

grin007 [14]3 years ago

7 0

Answer:

54

Explanation:

d = vo*t + ½*g*t²

d = 3*3 + ½*10*3²

d = 9 + 45

d = 54 m

entonces el objeto tiene 54 m de desplazamiento

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