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Margaret [11]
3 years ago
13

A company randomly selects 100 light bulbs every day for 40 days from its production process. If 600 defective light bulbs are f

ound in the sampled bulbs then the 3-sigma lower control limit would be
Physics
2 answers:
wel3 years ago
4 0

Answer:

3-sigma lower control limit=0.0429

Explanation:

Process average, p = 600 / (100*40)

=600/400  

=0.15

Lower Control Limit = p- 3 *sqrt (p*(1-p)/n)

= 0.15 - 3* (0.15*0.85/100)^0.5

=0.15-3*(0.1275/100)^0.5

= 0.0429

Therefore, the 3-sigma lower control =0.0429

lutik1710 [3]3 years ago
3 0

Answer:

3 sigma lower control limit = 0.0429

Explanation:

Given.

n = 100

days = 100

Number of defective bulbs = 600 defective bulbs

Let p = Process Average

p = 600/(100*40)

P = 600/4000

P = 0.15

q = 1 - p

q = 1 - 0.15

q = 0.85

3 sigma lower limit = p - 3*√(pq/n)

Using the above formula

Substitute in the values

3 sigma lower control limit = 0.15 - 3 * √(0.15 * 0.85/100)

3 sigma lower control limit= 0.15 - 3√0.001275

3 sigma lower control limit = 0.15 - 3* 0.035707142142714

3 sigma lower control limit = 0.15 - 0.107121426428142

3 sigma lower control limit = 0.04287857357185

3 sigma lower control limit = 0.0429 ---- approximated

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You can just use basic trigonometry to solve for the x & y components.

<span>vector a = 10cos(30) i + 10sin(30) j = <5sqrt(3), 5></span>

vector b is only slightly harder because the angle is relative to vector a, and not the positive x-axis. Anyway, this just makes vector b with an angle of 135deg to the positive x-axis.

<span>vector b = 10cos(135) i + 10sin(135) j = <-5sqrt(2), 5sqrt(2)></span>

So now we can do the questions:

r = a + b

r = <5sqrt(3)-5sqrt(2), 5+5sqrt(2)>

(a) 5sqrt(3)-5sqrt(2)

(b) 5+5sqrt(2)

(c)

|r| = sqrt( (5sqrt(3)-5sqrt(2))2 + (5+5sqrt(2))2 )

= 12.175

(d)

θ = tan-1 ( (5+5sqrt(2)) / (5sqrt(3)-5sqrt(2)) )

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<span> </span>

6 0
3 years ago
A 10v battery is connected in series with 2 resistors. R1 is 1 ohm and R2 is 4 ohms. What is the current that goes across R1?
Digiron [165]

Answer:

Current in circuit = 2 amp

Explanation:

Given:

Voltage of battery = 10 V

First Resistance R1 = 1 ohm

Second Resistance R2 = 4 ohm

Resistor connected in series

Find:

Current in circuit

Computation;

Resistor connected in series

So,

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Total resistance R = 1 ohm + 4 ohm

Total resistance R = 5 ohm

Current in circuit = V / R

Current in circuit = 10 / 5

Current in circuit = 2 amp

7 0
2 years ago
How much power is used in a machine that produces 15 Joules of work in 3 seconds? Use the formula P = W/t.
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7 0
3 years ago
In 1993 Ileana Salvador of Italy walked 3.0km in under 12min. Suppose that during her walk Salvador is observed to steadily incr
padilas [110]

The distance covered is 115 m

Explanation:

The motion of Ileana is a uniformly accelerated motion (constant acceleration), therefore we can use the following suvat equation:

s=(\frac{u+v}{2})t

where

s is the distance covered

u is the initiaal velocity

v is the final velocity

t is the time elapsed

In this problem, we have:

u = 4.20 m/s

v = 5.00 m/s

t = 25.0 s

Therefore, we can re-arrange the equation to find the distance covered:

s=(\frac{4.20+5.00}{2})(25.0)=115 m

Learn more about accelerated motion:

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5 0
3 years ago
Before Collision Consider a system to be one train car moving toward another train car at rest When the train cars collide, the
erma4kov [3.2K]

Answer:

2,400kg * m/s

Explanation:

You are missing some information in the question but the rest could be found some where else.

The question gives the masses and starting velocity of each car.

Car 1: m = 600kg and sv = 4m/s

Car 2: m 400kg and sv = 0m/s

Find the momentum of both cars.

Car 1: 600 * 4 = 2400

Car 2: 400 * 0 = 0

Add both.

2400 + 0 = 2400

Best of Luck!

7 0
3 years ago
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