Answer:
60 J
Explanation:
Given That
Coefficient of performance, CoP = 4.2
Quantity of heat of the refrigerator, Q = 250 J
Work done by the refrigerator, W = ?
First, it should be noted that the Coefficient of Performance can be said to be, the ratio of the Heat required to the Work done by the system. Mathematically written as,
CoP = Q / W
Since we are already given the values from our question, we can plug it in as it's a pretty straightforward question
4.2 = 250 / W, making W subject of formula, we have
W = 250 / 4.2
W = 60J
Thus, the Work done by the refrigerator is 60 J
