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3 years ago

While hammering a nail, you put in 30 Joules of work. The hammer then puts out 10 J of

Physics

2 answers:

Fynjy0 [20]3 years ago

8 0

Answer:

I think its 40%, pls correct me if I am wrong :(

Explanation:

AfilCa [17]3 years ago

3 0

Answer:

C Don't worry if you thought it was D. I almost answered that.

Explanation:

Remark

You can get this just by learning the vocabulary.

Efficiency = Work Out / Work In * 100%

Work in = 30J That's you swinging the hammer.

Work out = 10 J That's how much of the hammer's work gets to the nail.

Efficiency = (10/30)*100

Efficiency = 1/3 * 100

Efficiency = 33%

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Answer:

PE = 3.92x10^16J

potential energy

Explanation:

PE = m*g*h

mass of water = 1000kg/m³

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PE = (4*10^13kg)*(9.81m/s²)*(100m)

PE = 3.92x10^16J

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3 years ago

Two resistors of 2 ohms each are connected in parallel, another resistor of 1 ohm is connected in series with the parallel combi

insens350 [35]

Answer:

The power dissipated in either one of the parallel resistors is 2 V

Explanation:

Given;

two parallel resistors, R₁ and R₂ = 2 ohms

The total resistance of the Two resistors of 2 ohms connected in parallel is;

$R_T = \frac{R_1R_2}{R_1+R_2} = \frac{2*2}{2+2} = \frac{4}{4} = 1 \ ohm$

when connected to another resistor of 1 ohm in series, the total resistance becomes;

Rt = R₁ + R₂

Rt = 1 + 1 = 2 ohms

Current in the circuit, I = voltage / total resistance

= 2 /2 = 1 A

the overall circuit has been resolved to series connection, and current flow in series circuit is constant.

Power = I²R

Thus, power dissipated in either one of the parallel 2 ohms resistors is;

Power = I²R = (1)² x 2 = 2 V

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3 years ago

Hydraulic press is a force multiplier . show mathematically

Vadim26 [7]

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4 years ago

Identify an object that is similar to the shape of a planet.

lbvjy [14]

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3 years ago

Read 2 more answers

Intensity: Radiation of a single frequency reaches the upper atmosphere of the earth with an intensity of 1350 W/m2. What is the

sesenic [268]

Answer:

The right answer is "1010 V/m".

Explanation:

The given values are:

Intensity,

$I=1350 \ W/m^2$

$c = 3.00\times 108 \ m/s$

$\mu_0= 4\pi\times 10^{-7} \ T.m/A$

Now,

The electric field's maximum value will be:

= $\sqrt{2\times u\times c\times I}$

On substituting the values in the above formula, we get

= $\sqrt{2\times 4\times \pi\times 10^{-7}\times 3\times 10^8\times 1350}$

= $\sqrt{32400\times 3.14\times 10^{-7}\times 10^8}$

= $1010 \ V/m$

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3 years ago