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kupik [55]
3 years ago
10

At the zoo the polar bears are fed 7/9 bucket of fish a day. The penguins are fed 4/7 that amount. What fraction are the penguin

s fed?
Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0

Answer: They are fed 4/9 of what the polar bears are fed.


Step-by-step explanation:

7/9*4/7=

1/9*4/1=4/9

The 7's get cancelled out.

                                       


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Write and solve an equation based off the verbal phrase: 6 more than x is equal to 33
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Answer:

x + 6 = 33

Step-by-step explanation:

6 more than x means there's an increment in the value of x by addition of 6

x + 6 = 33

This leads to an algebraic linear equation. x is an unknown variable and can be solved for

we subtract 6 from both sides of the equation

x + 6 - 6 = 33 - 6

x = 27

Therefore, we can say 6 more than 27 is 33

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these tables of values represent continuous functions. for which function will the y-value be the greatest for very large values
Gelneren [198K]

Answer:

Option A.

Step-by-step explanation:

We need to find a table for which the y-value will be the greatest for very large values of x.

From the given table it is clear that the largest value of x in all tables is 5.

In table A, y=64 at x=5.

In table B, y=32 at x=5.

In table C, y=40 at x=5.

In table D, y=13 at x=5.

It is clear that 64 is the greatest value among 64, 32, 40 and 13.

It means table in option A represents the function for which the y-value will be the greatest for very large values of x.

Therefore, the correct option is A.

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7 0
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EX 6.1 How many iterations will the following for loops execute? for (int i = 0; i < 20; i+ +) { } for (int i = 1; i <= 20
Romashka-Z-Leto [24]

Answer:

20, 20, 15, 20, 10, and 5 iterations respectively

Step-by-step explanation:

The loop "for (int i = 0; i < 20; i+ +)" starts at i=0 and increases the counter i by 1 at the end of each iteration. The counter must be less than 20, so the values of i in the loop are 0,1,2,3,...,19. These are 20 values, and thus the code iterated 20 times.

The loop "for (int i = 0; i < 20; i+ +)" starts at i=1 and increases the counter i by 1 at the end of each iteration. The counter can't exceed 20, so the values of i in the loop are 1,2,3,4,...,20. These are 20 values, and thus the code iterated 20 times.

Similarly, in "for (int i = 5; i < 20; i+ +)" i takes the 15 values are 5,6,7,...,19. Hence, the code iterated 15 times.

The loop "for (int i = 20; i > 0; i- -)" starts at i=20 and decreases the counter i by 1 at the end of each iteration, so the values of i in the loop are 20,19,18,...,1. These are 20 values, then we have 20 iterations.

The loop "for (int i = 1; i < 20; i = i + 2)" starts at i=1 and increases the counter i by 2 at the end of each iteration. The values of i in the loop are 1,3,5,7,...,19. These are 10 values, and thus the code iterated 10 times.

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3 years ago
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