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igomit [66]
3 years ago
6

What compound is formed from a tight network of oppositely charged ions

Physics
1 answer:
Vsevolod [243]3 years ago
7 0

Answer:

salt

Explanation:

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Choose all the answers that apply.
Serhud [2]
<span>According to Newton's first law of motion:

-- objects at rest will remain at rest unless acted upon by an outside force

-- objects in motion will remain in motion unless acted upon by an outside force


</span>
8 0
3 years ago
A student places a block on a table and hangs one mass from the block. The student lets the block go and observes the block move
NeTakaya

Magnitude of acceleration

Explanation:

We know that acceleration can increase depending in the force applied on an object, any object with a greater mass will apply a greater force. F = M(a).

7 0
3 years ago
What is the relationship between the poles of a magnet? which direction does the magnet field move?
Assoli18 [71]
A magnet has a South Pole and a North Pole. South Pole and South Pole can't connect to her other, same as North and North. The same poles push each other away.
South Pole and North Pole connect.
4 0
3 years ago
A 4.1 object is lifted to a height of 4.5m above the surface of Earth.What is the potential energy of the object due to gravity?
liberstina [14]

Answer:

P = 180.81 J

Explanation:

Given that,

Mass of a object, m = 4.1 kg

It is lifted to a height of 4.5 m

We need to find the potential energy of the object due to gravity. It is given by the formula as follows :

P = mgh Where g is acceleration due to gravity

P = 4.1 kg × 9.8 m/s² × 4.5 m

P = 180.81 J

Hence, the potential energy is 180.81 J.

5 0
3 years ago
A steel cable has a cross-sectional area 4.49 × 10^-3 m^2 and is kept under a tension of 2.96 × 10^4 N. The density of steel is
Lemur [1.5K]

Answer:

The transverse wave will travel with a speed of 25.5 m/s along the cable.

Explanation:

let T = 2.96×10^4 N be the tension in in the steel cable, ρ  = 7860 kg/m^3 is the density of the steel and A = 4.49×10^-3 m^2 be the cross-sectional area of the cable.

then, if V is the volume of the cable:

ρ = m/V

m = ρ×V

but V = A×L , where L is the length of the cable.

m = ρ×(A×L)

m/L = ρ×A

then the speed of the wave in the cable is given by:

v = √(T×L/m)

  = √(T/A×ρ)

  = √[2.96×10^4/(4.49×10^-3×7860)]

  = 25.5 m/s

Therefore, the transverse wave will travel with a speed of 25.5 m/s along the cable.

7 0
3 years ago
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