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Anvisha [2.4K]
3 years ago
12

Two beams of coherent light travel different paths, arriving at point P. If the maximum destructive interference is to occur at

point P, what should be the path difference between the two waves?Two beams of coherent light travel different paths, arriving at point P. If the maximum destructive interference is to occur at point P, what should be the path difference between the two waves?The path difference between the two waves should be one and one-quarter of a wavelengths.The path difference between the two waves should be four wavelengths.The path difference between the two waves should be one-half of a wavelength.The path difference between the two waves should be one-quarter of a wavelength.The path difference between the two waves should be two wavelengths.The path difference between the two waves should be one wavelength.
Physics
1 answer:
Nimfa-mama [501]3 years ago
5 0

Answer:

The path difference between the two waves should be one-half of a wavelength

Explanation:

When two beams of coherent light travel different paths, arriving at point P. If the maximum destructive interference is to occur at point P , then the condition for it is that the path difference of two beams must be odd multiple of half wavelength. Symbolically

path difference = ( 2n+1 ) λ / 2

So path difference may be λ/2 , 3λ/ 2,  5λ/ 2 etc .

Hence right option is

The path difference between the two waves should be one-half of a wavelength.

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The amount of energy necessary to remove an electron from an atom is a quantity called the ionization energy, Ei. This energy ca
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Answer:

The value is E_i  =  1.5596 *10^{-18} \  J

Explanation:

From the question we are told that

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The velocity is v = 2.371*10^6 \ m/s

The mass of electron is m_e  =  9.109*10^{-31} \  kg

Generally the energy of the incident light is mathematically represented as

E =  \frac{h *  c}{\lambda}

Here c is the speed of light with value c =  3.0 *10^{8} \  m/s

h is the Planck constant with value h = 6.62607015 *  10^{-34 }  J\cdot s

So

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Generally the kinetic energy is mathematically represented as

E_k  =  \frac{1}{2} *  m_e * v^2

=> E_k  =  \frac{1}{2} *  9.109*10^{-31} * (2.371*10^6 )^2

=> E_k  =  2.56 *0^{-18} \  J

Generally the ionization energy is mathematically represented as

E_i  =  4.12 *10^{-18} -   2.56 *0^{-18}

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