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timama [110]
3 years ago
14

Jed drops a 18 kg box off of the Eiffel tower. After 6.1 seconds, how fast is the box moving (neglect air resistance.)

Physics
2 answers:
boyakko [2]3 years ago
4 0

Answer:

Speed, v = 60 m/s

Explanation:

Given that,

Mass of the box, m = 18 kg

Time, t = 6.1 seconds

Initially the box is at rest, u = 0

Let v is the final speed of the box i.e. after 6.1 seconds. We can calculate it using first equation of motion as :

v=u+at

Here, a = g

v=gt

v=9.8\times 6.1

v = 59.78 m/s

or

v = 60 m/s

So, after 6.1 seconds, the box is moving with a speed of 60 m/s. Hence, this is the required solution.

GuDViN [60]3 years ago
3 0
The box fall with acceleration 10m/s2 due to gravity

velocity/ 6.1 = 180
velocity = 1098 m/s

the answer is A.
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Please help on this one?
bezimeni [28]

Using the given equation you get:

E = 1.99x10^-25 / 9.0x10^-6

Divide 1.99 by 9.0: 1.99/9.0 = 0.22

For the scientific notation, when dividing subtract the two exponents:

25 -6 = 19

So you now have 0.22 x 10^-19

Now you need to change the 0.22 to be in scientific notation form:

2.2 x 10^-20

The answer is B.

3 0
3 years ago
PLEASE HURRYY!!!!The diagram shows two balls released from a device at the same time. The ball on the left falls freely from res
LenaWriter [7]

Answer:

i'm pretty sure its B but i may be wrong if you dont wanna take the chance wait for someone

Explanation:

4 0
3 years ago
Read 2 more answers
A bullet is fired horizontally at a height of 2 meters at a velocity of 930 m/s. Assume no air resistance. How far did the bulle
USPshnik [31]

Answer:

im pretty sure its a

Explanation:

4 0
3 years ago
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A Honda Hawk motorcycle and its rider with a combined mass of 450 kg travels around a curve of radius 106 m with a speed of 18 m
umka21 [38]

Answer: coefficient of static friction

= 0.31

Explanation: Since they negotiate the curve without skidding, the frictional force (F1) equals the centripetal force (F2).

F1= uN

F2 = M*(v²/r)

M is the combined mass 450kg

V is the velocity 18m/s

r is the radius 106m

N is the normal reaction 4410N

u is the coefficient of static friction

Making u subject of the formula we have that,

u = {450*(18²/106)} /4410

=1375.47/4410

=0.31

NOTE: coefficient of friction is dimensionless. It as no Unit.

7 0
3 years ago
At a race car driving event, a staff member notices that the skid marks left by the race car are
krok68 [10]

A car that experiences a deceleration of -41.62 m/s² and comes to a stop after 10.99 m has an initial velocity of 30.60 m/s.

A car experiences a deceleration (a) of -41.62 m/s² and comes to a stop (final velocity = v = 0 m/s) after 10.99 m (s).

We can calculate the initial velocity of the car (u) using the following kinematic equation.

v^{2} = u^{2} + 2as\\\\u = \sqrt[]{v^{2}-2as} = \sqrt[]{(0m/s)^{2}-2(-42.61m/s^{2} )(10.99m)} = 30.60m/s

A car that experiences a deceleration of -41.62 m/s² and comes to a stop after 10.99 m has an initial velocity of 30.60 m/s.

Learn more: brainly.com/question/14851168

5 0
2 years ago
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