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timama [110]
4 years ago
14

Jed drops a 18 kg box off of the Eiffel tower. After 6.1 seconds, how fast is the box moving (neglect air resistance.)

Physics
2 answers:
boyakko [2]4 years ago
4 0

Answer:

Speed, v = 60 m/s

Explanation:

Given that,

Mass of the box, m = 18 kg

Time, t = 6.1 seconds

Initially the box is at rest, u = 0

Let v is the final speed of the box i.e. after 6.1 seconds. We can calculate it using first equation of motion as :

v=u+at

Here, a = g

v=gt

v=9.8\times 6.1

v = 59.78 m/s

or

v = 60 m/s

So, after 6.1 seconds, the box is moving with a speed of 60 m/s. Hence, this is the required solution.

GuDViN [60]4 years ago
3 0
The box fall with acceleration 10m/s2 due to gravity

velocity/ 6.1 = 180
velocity = 1098 m/s

the answer is A.
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Refraction occurs when light passing from one medium to another. True or False
kodGreya [7K]

Answer: True

Refraction is a phenomenon in which the light bends or changes its direction (and changes the speed of propagation, as well) <u>when passing through a medium</u> with a refractive index n <u>different from the other medium.  </u>

Where the Refractive index is a number that describes how fast light propagates through a medium or material:

n=\frac{c}{v}

Being n a relation between the speed of light in vacuum c  and its speed in the other medium v .

It is important to note that in this process, the wavelength may be modified because it depends on the medium, however, the refracted ray of light does not change its frequency.

7 0
3 years ago
An example of potential energy is a ball sitting _____ of the stairs.
expeople1 [14]

Answer:

at the top

Explanation:

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3 0
4 years ago
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3 years ago
A convex mirror has a focal length of -12 cm. A lightbulb with
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4 0
3 years ago
Suppose a uniform electric field of 4 N/C is in the positive x direction. When a charge is placed at and fixed to the origin, th
Yuliya22 [10]

Answer:

E_total = 3 N / A

Explanation:

The electric field is a vector magnitude so when adding we must use vectors, in this case as the initial field E = 4N / c goes towards the axis axis and the field created by the fixed charge (E1) is also on the axis x we can add in scalar form.

               E_total = E + E₁

the expression for the field of a point charge is

                E₁ = k q₁ / r²

for the point x = 2m, they do not say that the total field is zero, so the charge q1 must be negative

                 E_total = E -k q₁ / r₂

we substitute

                   0 = E - k q₁ / r²

                   q₁ = \frac{E r^2}{k}

let's calculate

                   q₁ = \frac{4 \ 2^2}{9 \ 10^{-9}}

                   q₁ = 1.78 10⁻⁹ C

now we can calculate the field for position x = 4 m

                   E_total = 4 - 9 10⁹  1.78 10⁻⁹ / 4²2

                   E_total = 3 N / A

8 0
3 years ago
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