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timama [110]
3 years ago
14

Jed drops a 18 kg box off of the Eiffel tower. After 6.1 seconds, how fast is the box moving (neglect air resistance.)

Physics
2 answers:
boyakko [2]3 years ago
4 0

Answer:

Speed, v = 60 m/s

Explanation:

Given that,

Mass of the box, m = 18 kg

Time, t = 6.1 seconds

Initially the box is at rest, u = 0

Let v is the final speed of the box i.e. after 6.1 seconds. We can calculate it using first equation of motion as :

v=u+at

Here, a = g

v=gt

v=9.8\times 6.1

v = 59.78 m/s

or

v = 60 m/s

So, after 6.1 seconds, the box is moving with a speed of 60 m/s. Hence, this is the required solution.

GuDViN [60]3 years ago
3 0
The box fall with acceleration 10m/s2 due to gravity

velocity/ 6.1 = 180
velocity = 1098 m/s

the answer is A.
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(a)The acceleration of the 1,400-kg boat will be 0.425 m/sec²

(b) If it starts from rest, the distance through which the boat moves in 20.0 s will be 85 m.

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<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

Given data;

Forwad force acting on the boat,v₁ = 1,800-N

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The distance through which the boat moves is 20.0 s;

\rm x_f = x_ 0 + v_0 t + \frac{1}{2} at^2 \\\\ x_f  = \frac{1}{2}at^2 \\\\ x_f = 0+0 + \frac{1}{2} at^2 \\\\ x_f = \frac{1}{2}\times 0.425 \times (20 )^ 2 \\\\ x_f  = 85 \ m

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The velocity at the end of that time is found as;

\rm  v_f = v_ 0 + at \\\\ v_f =- 0+ at \\\\ v_f = 8.5 m/sec

Hence the acceleration of the boat, the distance through which the boat moves in 20.0 s, and velocity at the end of that time will be 0.425 m/sec²,85 m, and 8.5 m/sec.

To learn more about the velocity, refer to the link: brainly.com/question/862972

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