1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AleksAgata [21]
3 years ago
13

According to the graph above, how large of a force is needed in order to stretch the string 1.00 meters?

Physics
2 answers:
gulaghasi [49]3 years ago
7 0

My guess for this one would be; 400 N

My reasoning would be; it starts at 0 on both X and Y, if you need to get to 1.00 meters thats 4/4. 1/4 of 1.00 is .25, and on .25 its on 100 so multiply it by 4 to make 1.00 and you get 400 N

MrMuchimi3 years ago
6 0

Answer:

The needed force is 400 N.

Explanation:

We need to calculate the force for 1.00 m string

According to graph,

The force applied for stretch from 0.10 to 0.15 is 20 N.

0.10-0.15 = 0.05 m

So, the force applied is 20 N for 0.05 m.

For stretch 0.05 m = 20 N

For stretch 1 m = \dfrac{20}{0.05}= 400\ N

Hence, The needed force is 400 N.

You might be interested in
Which is NOT an INHERITED TRAIT?
Tcecarenko [31]
The answer is holes in leaves that were made by insects
6 0
3 years ago
Read 2 more answers
Only a body at rest has inertia.<br><br> - true<br> - false
geniusboy [140]

Answer:

false

Explanation:

inertia deals with movement!

8 0
3 years ago
Read 2 more answers
A solar panel is used to collect energy from the sun and change it into other forms of energy. The picture below shows some sola
irakobra [83]
C I’m pretty sure!!!!!
4 0
3 years ago
A tree loses water to the air by the process of transpiration at the rate of 110 g/h. This water is replaced by the upward flow
Ksivusya [100]

Answer:

The answer is 1.87nm/s.

Explanation:

The 110g/hr  water loss must be replaced by 110g/hr of sap. 110g of sap corresponds to a volume of  

110g \div \dfrac{1040*10^3g}{1*10^6cm^3}  = 106cm^3

thus rate of sap replacement is

106cm^3/hr = 106*10^{-6}m^3/3600s  = 2.94*10^{-8}m^3/s

The volume of sap in the vessel of length x is

V = Ax,

where A is the cross sectional area of the vessel.

For 2000 such vessels, the volume is

V = 2000Ax

taking the derivative of both sides we get:

\dfrac{dV}{dt} = 2000A \dfrac{dx}{dt}

on the left-hand-side \dfrac{dx}{dt} is the velocity v of the sap, and on right-hand-side \dfrac{dV}{dt}  = 2.94*10^{-8}m^3/s; therefore,

2.94*10^{-8}m^3/s=2000Av

and since the cross-sectional area is

A = \pi (\dfrac{100*10^{-3}m}{2} )^2 = 7.85*10^{-3}m^2;

therefore,

2.94*10^{-8}m^3/s =2000(7.85*10^{-3}m^2)v

solving for v we get:

v = \dfrac{2.94*10^{-8}m^3/s}{2000(7.85*10^{-3}m^2)}

\boxed{v =1.875*10^{-9}m/s = 1.875nm/s}

which is the upward speed of the sap in each vessel.

8 0
4 years ago
1d. Conservation of energy is demonstrated in this roller coaster example.
Dvinal [7]

Answer:

can you clear your question I can't understand

6 0
3 years ago
Other questions:
  • darrel noticed that his finger felt warmer in the ice water then did his left finger which of the following does the experiment
    7·2 answers
  • Oxygen and hydrogen gas are at the same temperature T.What is the ratio of kinetic energies of oxygen molecule and hydrogen mole
    10·1 answer
  • The process by which lithospheric plates move apart creating spaces that are filled with hot magma is called _____.
    5·2 answers
  • How do we calculate the "range" of the measurements?
    13·2 answers
  • A car travels at 20km/h for 60 mins how far does it travel
    9·1 answer
  • A chocolate brownie has a volume of 360cubic centimeters and a mass of 270grams. Calculate its density.
    11·1 answer
  • To test the strength of a retainment wall designed to protect a nuclear reactor,
    14·1 answer
  • A car 4m long moving at a velocity of 25m/s was beside a lorry 20m long with a velocity 19m/s at t=0. The distance between them
    6·1 answer
  • 26 POINTS!! will give brailest! can anyone help me? if you can't well, Merry Christmas!
    8·1 answer
  • When conducting objects (such as metals) are connected for a brief time, charge can be made to flow quite easily from one to the
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!