According to the graph above, how large of a force is needed in order to stretch the string 1.00 meters?
2 answers:
Answer:
The needed force is 400 N.
Explanation:
We need to calculate the force for 1.00 m string
According to graph,
The force applied for stretch from 0.10 to 0.15 is 20 N.
0.10-0.15 = 0.05 m
So, the force applied is 20 N for 0.05 m.
For stretch 0.05 m = 20 N
For stretch 1 m =
Hence, The needed force is 400 N.
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The electric field at one corner of a square is 1614217 N/C.
Explanation:
The distance between x and y direction diagonals.
As per the given details the distance between diagonals is calculated as
0.5² + 0.5² = c² => c = 0.707 m
Charge to the right: In x direction
In order to find the electric charge towards x direction
we use e = kq/r² formula
As 'k' is coulomb's constant it's value is 9 x N m²/C²
e = (9 x )(250 x
) / (0.5)²
e = 9 x N/C
Charge diagonal:
e = kq/r²
e = [(9 x )(250 x
) / (0.707)²] cos 45
e = 225000√2 N/C
X direction sum = 1218198 N/C.
Similarly as shown in x direction the charge is same for y direction also
Charge below: For y direction
e = kq/r²
e = (9 x )(250 x
) / (0.5)²
e = 9 x N/C
Charge diagonal:
e = kq/r²
e = [(9 x )(250 x
) / (0.5)²] sin 45
e = 159099 N/C
Y direction sum = 1059099 N/C
Resultant electric field strength:
1218198 ² + 1059099² = e²
e = 1614217 N/C [45 degrees below the horizontal]
Answer:
Explanation:
Current is the rate of flow of charge.
Answer:
Mass, m = 125 kg
Explanation:
Let us assume that the question says, "What is the mass of an object whose velocity is 400 m/s and the kinetic energy of 10⁷ J.
The kinetic energy of an object is :
So, the mass of the object is 125 kg.