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AleksAgata [21]
3 years ago
13

According to the graph above, how large of a force is needed in order to stretch the string 1.00 meters?

Physics
2 answers:
gulaghasi [49]3 years ago
7 0

My guess for this one would be; 400 N

My reasoning would be; it starts at 0 on both X and Y, if you need to get to 1.00 meters thats 4/4. 1/4 of 1.00 is .25, and on .25 its on 100 so multiply it by 4 to make 1.00 and you get 400 N

MrMuchimi3 years ago
6 0

Answer:

The needed force is 400 N.

Explanation:

We need to calculate the force for 1.00 m string

According to graph,

The force applied for stretch from 0.10 to 0.15 is 20 N.

0.10-0.15 = 0.05 m

So, the force applied is 20 N for 0.05 m.

For stretch 0.05 m = 20 N

For stretch 1 m = \dfrac{20}{0.05}= 400\ N

Hence, The needed force is 400 N.

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The ozone layer absorbs UV (ultraviolet) radiation. The answer is letter C. the ozone layer is able to oxidize the electros and photons in the UV rays so that the light that can pass through can be not harmful to humans.

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2 years ago
A small boy is playing with a ball on a stationary train. If he places the ball on the floor of the train, when the train starts
expeople1 [14]

A small boy is playing with a ball on a stationary train. If he places the ball on the floor of the train, when the train starts moving the ball moves toward the back of the train. This happened due to inertia

An object at rest remains at rest, or if in motion, remains in motion unless a net external force acts on it .  

When a train starts moving forward, the ball placed on the floor  tends to fall backward is an example of inertia of rest. Due to the reason that the lower part of the ball is in contact with the surface and rest of the part is not . As the train starts moving, its lower part gets the motion as the floor starts moving but the upper part will remain as it is as it is not in contact with the floor , hence do not attain any motion due to the inertia of rest simultaneously i.e. it tends to remain at the same place.

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8 0
1 year ago
Calculate the electric field at one corner of a square 50 cm on a side if the other corners are occupied by 250x10-7C (charges)
SIZIF [17.4K]

The electric field at one corner of a square is 1614217 N/C.

Explanation:

The distance between x and y direction diagonals.

As per the given details the distance between diagonals is calculated as

0.5² + 0.5² = c²  =>  c = 0.707 m

Charge to the right:  In x direction

In order to find the electric charge towards x direction

we use e = kq/r² formula

As 'k' is coulomb's constant it's value is 9 x 10^{9} N m²/C²

e = (9 x 10^{9})(250 x 10^{-7}) / (0.5)²

e = 9 x 10^{5} N/C

Charge diagonal:

e = kq/r²

e = [(9 x 10^{9})(250 x 10^{-7}) / (0.707)²] cos 45

e = 225000√2 N/C

X direction sum = 1218198 N/C.

Similarly as shown in x direction the charge is same for y direction also

Charge below:  For y direction

e = kq/r²

e = (9 x 10^{9})(250 x 10^{-7}) / (0.5)²

e = 9 x 10^{5} N/C

Charge diagonal:

e = kq/r²

e = [(9 x 10^{9})(250 x 10^{-7}) / (0.5)²] sin 45

e = 159099 N/C

Y direction sum = 1059099 N/C

Resultant electric field strength:

1218198 ² + 1059099² = e²

e = 1614217 N/C [45 degrees below the horizontal]

4 0
3 years ago
A large lightning bolt consists of a 18.2~\text{kA}18.2 kA current that moved 30.0~\text{C}30.0 C of charge. Assuming a constant
marissa [1.9K]

Answer:

1.65\times {-3} \text { s}

Explanation:

Current is the rate of flow of charge.

I=\dfrac{Q}{t}

t = \dfrac{Q}{I}

t = \dfrac{30.0}{18.2\times10^3} =1.65\times {0-3} = 1.65\times {-3} \text { s}

6 0
2 years ago
Read 2 more answers
¿Cuál es la masa de un objeto cuya masa es de 400 J y energía cinética de 107J?
Pachacha [2.7K]

Answer:

Mass, m = 125 kg

Explanation:

Let us assume that the question says, "What is the mass of an object whose velocity is 400 m/s and the kinetic energy of 10⁷ J.

The kinetic energy of an object is :

K=\dfrac{1}{2}mv^2\\\\m=\dfrac{2K}{v^2}\\\\m=\dfrac{2\times 10^7}{(400)^2}\\\\m=125\ kg

So, the mass of the object is 125 kg.

3 0
3 years ago
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