If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be
.
<h3>What is an escape velocity?</h3>
The ratio of the object's travel distance over a specific period of time is known as its velocity. As a vector quantity, the velocity requires both the magnitude and the direction. the slowest possible speed at which a body can break out of the gravitational pull of a certain planet or another object.
The formula to calculate the escape velocity of earth is given below:-
![V_e=\sqrt{\dfrac{2GM}{r}}](https://tex.z-dn.net/?f=V_e%3D%5Csqrt%7B%5Cdfrac%7B2GM%7D%7Br%7D%7D)
Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-
![V_e=\sqrt{\dfrac{2GM}{r\times 2}}](https://tex.z-dn.net/?f=V_e%3D%5Csqrt%7B%5Cdfrac%7B2GM%7D%7Br%5Ctimes%202%7D%7D)
.
Therefore, If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be
.
To know more about escape velocity follow
brainly.com/question/14042253
#SPJ4
To solve this problem we will apply the concepts related to wavelength as the rate of change of the speed of the wave over the frequency. Mathematically this is
![\lambda = \frac{v}{f}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7Bv%7D%7Bf%7D)
Here,
v = Wave velocity
f = Frequency,
Replacing with our values we have that,
![\lambda = \frac{340}{500}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7B340%7D%7B500%7D)
\lambda = 0.68m
The distance to move one speaker is half this
![\lambda/2 = 0.34m](https://tex.z-dn.net/?f=%5Clambda%2F2%20%3D%200.34m)
Therefore the minimum distance will be 0.34m
Answer:
the charge that is given by the object is positive charge and the object which is taking the charge is negetively charged
Explanation:
Answer:
Hold on Ill answer it..When do u need it by
Explanation: