Answer:
I think it is 1.67
Explanation:
I multiply the 45 and 27 cause it says rate of which means to multiply.
The solution to the questions are given as


- the direction of induced current will be Counterclock vise.
<h3>What is the direction of the
current induced in the loop, as viewed from above the loop.?</h3>
Given, $B(t)=(1.4 T) e^{-0.057 t}$




(b) 

c)
In conclusion, the direction of the induced current will be Counterclockwise.
Read more about current
brainly.com/question/13076734
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<span>Discrimination is illegal, but caste system is legal.
So answer: False</span>