Answer:
The magnitude of the average induced emf in the loop is 0.1 volts.
Explanation:
let Ф be the flux in the loop, B be the magnetic field and A be the area of the loop.
the induced emf in the loop is given by:
ε = - dФ/dt
= - d(B×A)/dt
= - A×d(B)/dt
= - π×r^2×d(B)/dt
= - π×(0.40)^2×(0.20 - (-0.30))/(2.5 - 0)
= 0.1 volt
Therefore, the magnitude of the average induced emf in the loop is 0.1 volts.
Answer:
Give me what kind of example you need please so I can help you. Put it in the comments.
Explanation:
(a) For constructive interference the two waves will have higher amplitude of 10 cm.
(b) For destructive interference the two waves will have zero amplitude.
<h3>
Amplitude of the waves for constructive interference </h3>
For constructive interference the two waves will have higher amplitude after constructive interference.
Resulting amplitude = 5 cm + 5cm = 10 cm
<h3>
Amplitude of the waves for destructive interference </h3>
For destructive interference the two waves will have zero amplitude after destructive interference.
Resulting amplitude = 5 cm - 5cm = 0
Learn more about amplitude here: brainly.com/question/413740
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