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KiRa [710]
3 years ago
13

When a wave slows down it...

Physics
2 answers:
tangare [24]3 years ago
8 0
<span>a. bends away from the normal</span>
ziro4ka [17]3 years ago
7 0
B towards the normal. When light enters a glass block, it slows down. A ray of light going from air to glass would be seen refracted towards the normal. 
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Calculate the energy released as heat when 51.60 g Cu 2 O ( s ) undergo oxidation at constant pressure.
lesya692 [45]

Answer:

Energy released as heat will be -189.417 Kj

Explanation:

The oxidation is the type of reaction in which reaction occurs in the presence of oxygen. The exothermic reaction is the type of reaction in which heat is released. The enthalpy is the type of physical quantity that is used to measure the energy in the thermodynamic system.

As we know the molar mass of Copper II Oxide is 79.545 g

Also the oxidation of  copper(II) oxide, CuO(s), is an exothermic process, 2Cu2O (s) + O2-->4CuO (s) delta H reaction= -292.0 kj/mol.

So for 51.60g of Copper II Oxide,

Heat released will be (-292.0 * 51.60/79.545) = -189.417 Kj

6 0
3 years ago
If the amount of matter of something is increased
lakkis [162]

Answer:

I need the question first lol

Explanation:

7 0
3 years ago
In a slap shot, a hockey player accelerates the puck from a velocity of 8.00 m/s to 40.0 m/s in the same direction. If this shot
posledela

We use the equations of motion,

v = u + at                                               (A)

v^{2} = u^{2} + 2as                                (B)

Here, v is final velocity of the body, u is initial velocity of the body, a is the acceleration of the body, t is the time taken in the motion and s is distance traveled by the body.

Given u = 8 \ m/s, v = 40 \ m/s and t = 3.33 \times 10^{-2} \ s.

So, from equation (A)

40 \ m/s = 8 \ m/s + a ( 3.33 \times 10^{-2 } \ s) \\\\ a =  \frac{32 \ m/s}{3.33\times 10^{-2 } \ s  }  = 9.6 \times 10^{2} \ m/s^2

Now from the  equation (B),

(40 \ m/s)^2 = (8 \ m/s)^2 + 2 (9.6 \times 10^{2} m/s^2) \times s  \\\\ s = \frac{(40 \ m/s)^2-(8 \ m/s)^2}{2 (9.6 \times 10^{2} m/s^2} = 0.8 \ m

Thus, the distance over which the puck accelerates is 0.8 m.

6 0
3 years ago
Solve v= d/t for t when d=30 and v=200​
Alisiya [41]
X-4y+5z=0,x+z-3y=0
6x-y+4z=0,x-7y+z=0
x+y-z=3, 2x-8y+13z=1


Hope this helped!
8 0
3 years ago
Comparing sound waves with different frequencies and wavelengths traveling through air,
aleksklad [387]

Explanation:

The speed of sound wave only depends on the property of the medium like density and the bulk modulus of the medium particle. The speed of sound also depends on the temperature of the medium.

On comparing sound waves with different frequencies and wavelengths traveling through air, the speed of the wave doesn’t depend on the frequency or the wavelength. Hence, the correct option is (1).

4 0
3 years ago
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