Question

A uniform magnetic field of magnitude 0.23 T is directed perpendicular to the plane of a rectangular loop having dimensions 7.8 cm by 14 cm. Find the magnetic flux through the loop.

Answer 1

Answer:

Ф = 2.51mWb

Explanation:

Given Area 7.8cm by 14cm= 109.2cm² = 109.2×10‐⁴m²

B = 0.23T.

Ф = BACosθ

Ф = magnetic flux through the area.

B = magnetic field strength

A = Area of the loop through which there is a magnetic flux.

θ = angle between the normal to the area and the direction of the magnetic field. The normal is a perpendicular line directed out of the plane of the loop. It is a vector for the area.

Assuming that the normal to the area is perpendicular to the magnetic field vector, that is θ = 0° ,

Ф = 0.23 × 109.2×10-⁴ Cos0° = 2.51×10-³Wb = 2.51mWb.

Answer 2

Answer:

0.0025116weber/m²

Explanation:

Magnetic field density (B) is the ratio of the magnetic flux (¶) through the loop to its cross sectional area (A).

Mathematically;

B = ¶/A

¶ = BA

Given B = 0.23Tesla which is the magnitude of the magnetic field

Dimension of the rectangular loop = 7.8 cm by 14 cm

Area of the rectangular loop perpendicular to the field B = 7.8cm×14cm

= 109.2cm²

Converting this value to m²

Area of the loop = 109.2 × 10^-4

Area of the loop = 0.01092m²

Magneto flux = 0.23×0.01092

Magnetic flux = 0.0025116weber/m²