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Marrrta [24]
3 years ago
7

A friend on skis stands still on level ground, with dry 0.00°C with a coefficient of static friction of 0.0300. How hard would y

ou have to push your friend in the forward horizontal direction to move him if your friend weighs 685 N?​
Physics
1 answer:
Salsk061 [2.6K]3 years ago
6 0

Answer:

20.6 N

Explanation:

Friction equals normal force times coefficient of friction.

F = Fn μ

On level ground, normal force equal weight.

Fn = W

Therefore:

F = W μ

F = (685 N) (0.0300)

F = 20.6 N

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Assuming the wall is frictionless, there are four forces acting on the ladder.

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Friction force pushing to the right at the foot of the ladder (Ff).

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Take the sum of the forces in the x direction.

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Ff = Rw

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(c) State the reaction at the foot of the ladder.

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Answer:

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