Answer:
Mass of O₂ present in the room: 185200 g
185.2 kg
Quantity of O₂ = 5787.5
Explanation:
The ideal gases Law can solved, what is ths mass of O₂ present in the room, or the quantity of O₂ (moles), present in the room.
P . V = n . R . T
P = 1 atm
V = volume of the room
n = moles
R = 0.082 L.atm/mol.K
T = T° in K
T° C + 273 → 22°C + 273 = 295K
Let's find out the volume of the room
7 m . 8 m . 2.5 m = 140 m³
Units of R, are in L, so we must convert m³ to dm³
1dm³ = 1 L
140m³ . 1000 = 140000 dm³
1.4x10⁵L
1 atm . 1.4x10⁵L = n . 0.082 L.atm/mol.K . 295K
(1 atm . 1.4x10⁵L) / (0.082 L.atm/mol.K . 295K) = n
5787.5 moles = n
molar mass . moles = mass
5787.5 moles O₂ . 32 g/m = 185200 g of O₂

moles of hydrogen in reaction =
=
= 0.996 mol
ratio of

: Na is 1 : 2
∴ if mol of

= 0.996 mol
then mol of Na = (0.996 mol * 2)
= 1.99 mol
Mass of Na = molar mass * mol
= (22.99 g / mol) * (1.99 mol)
= 45.78 g
Note:
1) Molar Mass is the mass of an element measured in grams.
2) According to Avogadro's Law, the same volume of different gases at the same condition of Temperature and Pressure contain the same number of particles. From this law we know that at STP, one mole of gas occupies 22.4 L of volume (molar volume).
3) By calculating the mole of one specie in a reaction, one can use mole ratio based on the stoichimectric values (values used to balance the equation) given to the species upon balancing the equation to find the moles of another species.
Answer:
Adding a concentrated salt solution to the solution containing cheek cells will cause the water to move outside the cells by osmosis. The cheek cells are at a higher water potential than the outside solution so, the water will move out, down the water potential gradient, until an equilibrium is reached.
Hope that answers the question, have a great day!
Answer:
D
Explanation:
Light blubs are not made of fire.
The sun wasnt made by humans.
You cant find Light bulbs in nature.
Meaning it is D.
Answer:
All of these properties are due to the chemical structure of the compound. The chemical structure includes the bonding angle, the type of bonds, the size of the molecule, and the interactions between molecules. Slight changes in the chemical structure can drastically affect the properties of the compound.
Explanation:
Hope it helps.
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