What is the limiting reactant when 4 mol P4 and 4 mol S8 react.
1 answer:
Taking into account the reaction stoichiometry, P₄ will be the limiting reagent.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
8 P₄ + 3 S₈ → 8 P₄S₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- P₄: 8 moles
- S₈: 3 moles
- P₄S₃: 8 moles
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
<h3>Limiting reagent in this case</h3>To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 3 moles of S₈ reacts with 8 moles of P₄, 4 moles of S₈ reacts with how many moles of P₄?
<u><em>moles of P₄= 10.667 moles</em></u>
But 10.667 moles of P₄ are not available, 4 moles are available. Since you have less amount of moles than you need to react with 4 moles of S₈, P₄ will be the limiting reagent.
Learn more about the reaction stoichiometry:
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<h2>Hello!</h2>
The answer is: -97.37° C
<h2>Why?</h2>According to the Charles and Gay-Lussac's Law we have that:
Where:
<em>v</em> is the volume of the gas
<em>t</em> is the temperature of the gas
<em>k </em>is the proportionality constant
From the Gay-Lussac's Law we also have the following relation:
Since we need to find the new temperature (T2) we can use the last equation:
We are asked to find the temperature in Celsius degrees, so, we must convert the result (in K) to Celsius degrees:
So, the temperature is -97.37° C
Have a nice day!