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3 years ago

6

B) Name three substances which can undergo sublimation and deposition respectively

1 answer:

SpyIntel [72]3 years ago

3 0

solid carbon dioxide, iodine, arsenic, and naphthalene

Explanation:

Examples of substances that undergo sublimation

Examples of solids that sublime are dry ice (solid carbon dioxide), iodine, arsenic, and naphthalene (the stuff mothballs are made of).

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How many moles of Chromium(III) nitrate (Cr(NO3)3) are produced when Chromium reacts with 0.85 moles of Lead(IV) nitrate (Pb(NO3

Sedbober [7]

Answer:

$0.64molCr(NO_3)_3$

Explanation:

Hello there!

In this case, according to the given chemical equation, it turns out possible for us to realize there is a 4:3 mole ratio of chromium(III) nitrate to lead(IV) nitrate, and therefore, we can calculate the moles of the former by applying the shown below stoichiometry setup:

$0.85molPb(NO_3)_4*\frac{3molCr(NO_3)_3}{4molPb(NO_3)_4} \\\\0.64molCr(NO_3)_3$

Regards!

7 0

4 years ago

ANALOGY: monatomic is to O as _____________is to O2.

ahrayia [7]

Monatomic is one atom.

Diatomic is two atoms.

d. diatomic

8 0

3 years ago

Read 2 more answers

Ede4ka [16]

Answer:

Explanation:

E

6 0

3 years ago

Enter your answer in the provided box. A person's blood alcohol (C2H5OH) level can be determined by titrating a sample of blood

Annette [7]

<u>Answer:</u> The mass percent of alcohol in blood is 0.183 %

<u>Explanation:</u>

To calculate the moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of $Cr_2O_7^{2-}$ solution = 0.05961 M

Volume of solution = 35.46 mL = 0.03546 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.05961M=\frac{\text{Moles of }Cr_2O_7^{2-}}{0.03546L}\\\\\text{Moles of }Cr_2O_7^{2-}=(0.05961mol/L\times 0.03546L)=2.11\times 10^{-3}mol$

The given chemical reaction follows:

$16H^+(aq.)+2Cr_2O_7^{2-}(aq.)+C_2H_5OH(aq.)\rightarrow 4Cr^{3+}(aq.)+2CO_2(g)+11H_2O(l)$

By Stoichiometry of the reaction:

2 moles of dichromate ions react with 1 mole of ethanol.

So, $2.11\times 10^{-3}mol$ of dichromate ions will react with = $\frac{1}{2}\times 2.11\times 10^{-3}=1.06\times 10^{-3}mol$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of ethanol = $1.06\times 10^{-3}mol$

Molar mass of ethanol = 46.07 g/mol

Putting values in above equation, we get:

$1.06\times 10^{-3}mol=\frac{\text{Mass of ethanol}}{46.07g/mol}\\\\\text{Mass of ethanol}=(1.06\times 10^{-3}mol\times 46.07g/mol)=0.0488g$

To calculate the mass percent of ethanol in blood, we use the equation:

$\text{Mass percent of ethanol}=\frac{\text{Mass of ethanol}}{\text{Mass of blood plasma}}\times 100$

Mass of blood plasma = 26.60 g

Mass of ethanol = 0.0488 g

Putting values in above equation, we get:

$\text{Mass percent of ethanol}=\frac{0.0488g}{26.60g}\times 100=0.183\%$

Hence, the mass percent of alcohol in blood is 0.183 %

5 0

3 years ago

How many moles of NaCl are contained in 100.0 mL of a 0.20 M solution?

AURORKA [14]

Answer:

0.02 mol.

Explanation:

8 0

3 years ago