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yulyashka [42]
3 years ago
14

A ball is thrown vertically upward with a speed of 25.0 m/s from a height of 2.0 m.

Physics
1 answer:
Marrrta [24]3 years ago
4 0

Answer:

The answer to your question is

a) t = 2.55 s

b) t = 5.5 s

Explanation:

Data

vo = 25 m/s

h = 2 m

g = 9.81 m/s

Formula

t = -(vo)/g

a)

        t = -(25)/9.81

        t = 2.55 s

b)

        Tt = 2t

         Tt = 2(2.55)

         Tt = 5.1 s

Time in the last 10 m

         10 = 25t + (1/2)(9.81)t²

Simplify

          10 = 25t 4.91t²

          4.9t² + 25t - 10 = 0

Solve the equation using an online calculator

    t₁ = 0.37 s               t₂ = -5.47 s

The correct answer is t₁, t₂ is incorrect because there are no negative answers.

Total time = 5.1 + 0.37

                 = 5.5 s

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GrogVix [38]
This is a sneaky trick question, to help you discover whether you know
one of the differences between velocity and speed.
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If you make a list of the distances and directions, and ignore the times,
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4 - west,  (3 + 1) - east . . . . .  zero in the east/west direction

1.5 - north,  1.5 - south . . . . . zero in the north/south direction

This jogger went out, had a nice jog around the neighborhood,and ended up exactly where he started.

Average velocity = (distance between start point and end point) / (time)

IF the question asked for average SPEED, then you would need the total distance, and divide it by the total time.  But it asks for VELOCITY, and <u>that</u> only involves the straight distance between the start point and the end point, regardless of the route taken in between.

The jogger ended up exactly where he started.  The distance between start and end points was zero.  Average velocity is  (zero) / (time) .  And that fraction is going to be <em><u>Zero</u></em>, no matter how long or how short the trip was, and no matter how much time it took.


3 0
3 years ago
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Furkat [3]

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What is the energy of a photon of blue light with a frequency of 6.53 × 10¹4 Hz?
shusha [124]

Answer:

V = 6.53 × 10^14

h = 6.626 × 10^-34

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An object is 45.0 cm from a converging lens and the object is 1.90 cm tall. What is the position and height and orientation of t
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Height: 0.62 cm

Orientation: Inverted.

Explanation:

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\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\\\Rightarrow \frac{1}{v}=\frac{1}{f}+\frac{1}{u}\\\Rightarrow \frac{1}{v}=\frac{1}{11}+\frac{1}{-45}\\\Rightarrow v=\frac{11\times 45}{45-11}\\\Rightarrow v=14.6\ cm

\frac{h_i}{h_o}=\frac{d_i}{d_o}\\\Rightarrow h_i=h_o\times \frac{d_i}{d_o}\\\Rightarrow h_i=1.9\times \frac{14.6}{-45}\\\Rightarrow h_i=-0.62 cm

Height: 0.62 cm

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