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yulyashka [42]
3 years ago
14

A ball is thrown vertically upward with a speed of 25.0 m/s from a height of 2.0 m.

Physics
1 answer:
Marrrta [24]3 years ago
4 0

Answer:

The answer to your question is

a) t = 2.55 s

b) t = 5.5 s

Explanation:

Data

vo = 25 m/s

h = 2 m

g = 9.81 m/s

Formula

t = -(vo)/g

a)

        t = -(25)/9.81

        t = 2.55 s

b)

        Tt = 2t

         Tt = 2(2.55)

         Tt = 5.1 s

Time in the last 10 m

         10 = 25t + (1/2)(9.81)t²

Simplify

          10 = 25t 4.91t²

          4.9t² + 25t - 10 = 0

Solve the equation using an online calculator

    t₁ = 0.37 s               t₂ = -5.47 s

The correct answer is t₁, t₂ is incorrect because there are no negative answers.

Total time = 5.1 + 0.37

                 = 5.5 s

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3 years ago
a spring has a force constant of 100 n/m and an unstretched length of 0.07 m. one end is attached to a post that is free to rota
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6 0
1 year ago
Where is the near point of an normal eye when accidentally wear a contact lens with a power of +2.0 diopters?
Lerok [7]

Answer:

The near point of an eye with power of +2 dopters, u' = - 50 cm

Given:

Power of a contact lens, P = +2.0 diopters

Solution:

To calculate the near point, we need to find the focal length of the lens which is given by:

Power, P = \frac{1}{f}

where

f = focal length

Thus

f = \frac{1}{P}

f = \frac{1}{2} = + 0.5 m

The near point of the eye is the point distant such that the image formed at this point can be seen clearly by the eye.

Now, by using lens maker formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{u'}

where

u = object distance = 25 cm = 0.25 m = near point of a normal eye

u' = image distance

Now,

\frac{1}{u'} = \frac{1}{f} - \frac{1}{u}

\frac{1}{u'} = \frac{1}{0.5} - \frac{1}{0.25}

\frac{1}{u'} = \frac{1}{f} - \frac{1}{u}

Solving the above eqn, we get:

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7 0
3 years ago
A short current element dl⃗ = (0.500 mm)j^ carries a current of 4.80 A in the same direction as dl⃗ . Point P is located at r⃗ =
sammy [17]

Answer:

Magnetic field in Tesla: 1.65*10^−10 T,   0,   3.09*10^−10 T

Explanation:

Given data:

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Attached below is the detailed solution

7 0
3 years ago
A car with a mass of 600 kg is traveling at a velocity of 10 m/s. How much kinetic energy does it have?
Viefleur [7K]

Answer:

KE = 30,000 J

Explanation:

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KE = \frac{1}{2} (600)(100)

KE = \frac{1}{2} (60000)

KE = 30,000 J

5 0
3 years ago
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