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3 years ago

Natural frequency is determined by an instrument’s:

Physics

1 answer:

belka [17]3 years ago

8 0

A. Material, because it's the same for each version of that element.

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Convert 13.6g/cm3 into kg/m3

Wewaii [24]

Answer:

0.000136kg/m3

Explanation:

13.6 / 1000 = 0.0136kg/cm3

0.0136 / 100 = 0.000136kg/m3

5 0

3 years ago

An aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The el

Alborosie

Answer:

I = 4.75 A

Explanation:

To find the current in the wire you use the following relation:

$J=\frac{E}{\rho}$ (1)

E: electric field E(t)=0.0004t2−0.0001t+0.0004

ρ: resistivity of the material = 2.75×10−8 ohm-meters

J: current density

The current density is also given by:

$J=\frac{I}{A}$ (2)

I: current

A: cross area of the wire = π(d/2)^2

d: diameter of the wire = 0.205 cm = 0.00205 m

You replace the equation (2) into the equation (1), and you solve for the current I:

$\frac{I}{A}=\frac{E(t)}{\rho}\\\\I(t)=\frac{AE(t)}{\rho}$

Next, you replace for all variables:

$I(t)=\frac{\pi (d/2)^2E(t)}{\rho}\\\\I(t)=\frac{\pi(0.00205m/2)^2(0.0004t^2-0.0001t+0.0004)}{2.75*10^{-8}\Omega.m}\\\\I(t)=4.75A$

hence, the current in the wire is 4.75A

4 0

3 years ago

Why must the electric field be normal to the surface at every point of a charged conductor?

solong [7]

-- If the field were inclined to the surface, then it would have
some component parallel to the surface.

-- Then, since we're talking about a conductor, the charges
on the object would move in response to that component
of the field, until there was no longer any component of the
field trying to move them.

3 0

3 years ago

A ball whirls around in a vertical circle at the end of a string. The other end of the string is fixed at the center of the circ

never [62]

Answer:

$T_b=m(g+\frac{v_b^2}{R})$

Explanation:

At the bottom the tension would be upwards and the weight downwards, their difference being the centripetal force. Taking the upwards direction as positive we then have:

$T_b-mg=F_{cp}=ma_{cp}=m\frac{v_b^2}{R}$

where we have used the equation for centripetal acceleration. Thus we have:

$T_b=m(g+\frac{v_b^2}{R})$

4 0

3 years ago

If the temperature of an iron sphere is increased

lesya692 [45]

<h2>Answer: its density will decrease</h2>

By increasing the temperature of the iron sphere, its volume will increase (due to the material of which it is composed), this is a phenomenon known as<em> thermal dilation</em>. However, the mass of the sphere will remain the same.

On the other hand, density $D$ is a characteristic property of substances and materials and is defined as the relationship between the mass $m$ and volume $V$ of a specific substance or material, as shown below:

$D=\frac{m}{V}$

This means <u>density is inversely proportional to volume</u>. Therefore, increasing the temperature of the iron sphere, its volume will be increased and <em><u>its density will be decreased</u></em>.

5 0

3 years ago