<em><u>pic </u></em><em><u>attached</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em><em><u> </u></em>
<em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>(ʘᴗʘ✿)</u></em>
Answer: 3.2
Explanation:
pH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
Thus as pH and are inversely related, a solution having lower pH will have more amount of concentration. And a solution having more pH will have less amount of concentration.
Thus the solution with lowest pH of 3.2 will have highest hydronium ion concentration.
Answer:
A) 800 N
B) 865.28 N
C) 734.28 N
Explanation:
Given,
The weight of the woman, W = 800 N
Therefore, the mass of the women is
m = W/g
= 800/9.8
= 81.53 Kg
A) If the elevator is ascending with a constant velocity, the external acceleration of the body is zero,
Then the elevator readings are
W = mg + ma
= 800 + 0
= 800 N
The elevator reading of the person ascending at constant velocity W = 800 N
B) Ascending at a constant acceleration of 0.8 m/s²
Then the elevator reading are
W = mg + ma
= 800 + (81.65 x 0.8)
= 865.28 N
The elevator reading ascending at constant acceleration is, W = 865.28 N
C) The elevator reading descending at constant acceleration,
W = 800 + (81.65 x 0.8)
= 734.72 N
Hence, the elevator reading descending at constant acceleration is, W = 734.72 N
Answer:
see that this shock is completely elastic
Explanation:
In this case we have the collision of two bodies, so that the moments conserve we must define a system in such a way that the forces during the crash are internal, this system is the one formed by the two bodies
let's write the moment in two moments
initial instant. Before the crash
p₀ = m₁ v₁_i + m₂ v₂_i
final moment. Right after the crash
pf = m₁ v₁_f + m₂ v₂_f
to define what kind of shock we have we use the recovery constant
po = e pf
where the term e, called the recovery constant, determines the type of shock we have, for a perfectly elastic shock it is worth 1 and for an inelastic shock it is worth 0
let's substitute the values
2 9 - 3 3 = e (2 1,5 + 3 2)
9 = e 9
e = 1
therefore we see that this shock is completely elastic