Unit price:
$3.03 for a gallon of gass
$0.05 per ounce of soap
$0.75 per bag of popcorn
Not a Unit Price:
$20 for 5 books
$33.00 for 2 avocadoes
hoped that helped
Answer: m² + 3m - 10 = 0
Step-by-step explanation:
From the expression, considering
6x + 5 = m
The original expression
( 6x + 5 )² - 10 = -18 - 15
Factorize the right hand expression,
-18 - 15 = -3( 6x - 15 )
Since m = 6x + 5 , we now substitute for m in that expression
m² - 10 = -3m
Now re arrange the equation in the form,
ax² - bx + c = 0
Now back to the equation,
m² + 3m - 10 = 0,
So the equivalent equation will be
m² + 3m - 10 = 0
Step-by-step explanation:
YOU JUST FOLLOW THE STEP
<span>If there has to be 2 men and 2 women, we know
that we must take a group of 2 men out of the group of 15 men and a group of 2
women out of the group of 20 women. Therefore, we have:
(15 choose 2) x (20 choose 2)
(15 choose 2) = 105
(20 choose 2) = 190
190*105 = 19950
Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>
<span>If there has to be 1 man and 3 women, we know
that we must take a group of 1 man out of the group of 15 men and a group of 3
women out of the group of 20 women. Therefore, we have:
(15 choose 1) x (20 choose 3)
(15 choose 1) = 15
(20 choose 3) = 1140
15*1140 = 17100
Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>
<span>We now find the total outcomes of having a group
with 4 women.
We know this is the same as saying (20 choose 4) = 4845</span>
Therefore, there are 4845 ways to have a group of
4 with 4 women.
We now add the outcomes of 2 women, 3 women, and
4 women and get the total ways that a committee can have at least 2 women.
19950 + 17100 + 4845 = 41895 ways that there will
be at least 2 women in the committee
