If (x)=-2377 +3 and V(x)= x, what is the range of (LOV)(x)?
1 answer:
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Table:
y = x²
can also be written as: f(x) = x²
Plug in each x value and calculate the output:
f(-4) = (-4)² = 16
f(-3) = (-3)² = 9
f(-2) = 4
f(-1) = 1
f(-) =
f(0) = 0
f() =
f(1) = 1
f(2) = 4
f(3) = 9
f(4) = 16
Answers:
a) graph shown in picture
b) vertex is at (0, 0)
Answer:
<u>Given function</u>
- h(x) = 2x - 1
#15 Find the inverse of h(x)
<u>Substitute x with y and h(x) with x and solve for y:</u>
- x = 2y - 1
- 2y = x + 1
- y = 1/2x + 1/2
<u>The inverse is:</u>
- h⁻¹(x) = 1/2x + 1/2
#16 The graph with both lines is attached.
The x- and y-intercepts of both functions have reversed values.
#17 Table of the inverse function will contain same numbers with swapped domain and range.
<u>Initial look is like this:</u>
- <u>x | -3 | -2 | -1 | 0 | 1 | 2 | 3</u>
- h⁻¹(x) | -1 | | 0 | | 1 | | 2
<u>The rest of the table is filled in by finding the values:</u>
- <u>x | -3 | -2 | -1 | 0 | 1 | 2 | 3</u>
- h⁻¹(x) | -1 | -0.5 | 0 | 0.5 | 1 | 1.5 | 2
The equation of the line in point-slope form is: C. y − 5 = −(x − 2).
<h3>What is the Point-Slope Equation of a Line?</h3>A line with a slope (m) and a point (a, b) is represented in point-slope form as, y - b = m(x - a).
Slopes of perpendicular lines are negative reciprocals of each other. Find the slope of the line in the graph given as follows:
Slope (m) = rise/run = 3 units/3 units = 1
Negative reciprocal of 1 is -1.
The slope of the line would be m = -1.
Substitute m = -1 and (a, b) = (2, 5) into y - b = m(x - a) to wrote the equation:
y - 5 = -1(x - 2)
y − 5 = −(x − 2)
Learn more about point-slope form on:
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