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4 years ago

Stereotypes are widely held beliefs that people have certain traits because

Physics

1 answer:

Ray Of Light [21]4 years ago

4 0

Answer:

Stereotypes are widely held beliefs that people have certain traits because they belong to a particular group stereotypes are often in accurate and frequently portray the members of less powerful less controlling groups or negatively and members of more powerful more controlling groups.

You might be interested in

what kind of wave would be observed in outer space between planets where there is very little matter?

ddd [48]

Shock waves can be observed in outer space between planets where there is very little matter. Although little, plasma does exist in outer space which allows the waves to travel.

5 0

3 years ago

A particle moves with acceleration function a(t) = 5 + 4t - 2t^2. Its initial velocity v(0) = 3 m/s and its initial displacement

eimsori [14]

Answer:

Its position after 4 seconds is 62 meters.

Explanation:

It is given that,

The acceleration of the particle is given by equation :

$a(t)=5+4t-2t^2$

Also, $a=\dfrac{dv}{dt}$

$v=\int\limits {a.dt}$

$v=\int\limits {(5+4t-2t^2).dt}$

$v=5t+2t^2-\dfrac{2}{3}t^3+c$

At t = 0, $v(0)=3\ m/s$ . So, c = 3

$v=5t+2t^2-\dfrac{2}{3}t^3+3$

Also, $v=\dfrac{ds}{dt}$ , s is the position

$s=\int\limits {v.dt}$

$s=\int\limits {(5t+2t^2-\dfrac{2}{3}t^3+3).dt}$

$s=\dfrac{5}{2}t^2+\dfrac{2}{3}t^3-\dfrac{t^4}{6}+3t+c'$

At t = 0, $s(0)=10\ m$ . So, c' = 10

$s=\dfrac{5}{2}t^2+\dfrac{2}{3}t^3-\dfrac{t^4}{6}+3t+10$

At t = 4 s

$s=\dfrac{5}{2}(4)^2+\dfrac{2}{3}(4)^3-\dfrac{(4)^4}{6}+3(4)+10$

s = 62 m

So, at t = 4 seconds the position of the particle is 62 meters. Hence, this is the required solution.

5 0

3 years ago

The mean time between collisions for electrons in room temperature copper is 2.5 x 10-14 s. What is the electron current in a 2

Darya [45]

Answer:

1.87 A

Explanation:

τ = mean time between collisions for electrons = 2.5 x 10⁻¹⁴ s

d = diameter of copper wire = 2 mm = 2 x 10⁻³ m

Area of cross-section of copper wire is given as

A = (0.25) πd²

A = (0.25) (3.14) (2 x 10⁻³)²

A = 3.14 x 10⁻⁶ m²

E = magnitude of electric field = 0.01 V/m

e = magnitude of charge on electron = 1.6 x 10⁻¹⁹ C

m = mass of electron = 9.1 x 10⁻³¹ kg

n = number density of free electrons in copper = 8.47 x 10²² cm⁻³ = 8.47 x 10²⁸ m⁻³

$i$ = magnitude of current

magnitude of current is given as

$i = \frac{Ane^{2}\tau E}{m}$

$i = \frac{(3.14\times 10^{-6})(8.47\times 10^{28})(1.6\times 10^{-19})^{2}(2.5\times 10^{-14}) (0.01)}{(9.1\times 10^{-31})}$

$i$ = 1.87 A

4 0

3 years ago

Consider the following system, where F = 80 N, m = 1 kg, and M = 11 kg M m F What is the magnitude of the force with which one b

Lorico [155]

Answer:

Force exerted by the lighter block on the heavier block is 6.63 N

Explanation:

Given Data

F = 80N

m = 1kg

M = 11kg

Solution:

*We assume that there is no friction

Calculating the acceleration of the system

a = $\frac{F}{m+M}$

a = $\frac{80}{1+11}$

a = $\frac{80}{12}$

a = 6.67m $s^{-2}$

Let's write the Equation of Motion of the heavier block

$F_{1}$ = F - $F_{2}$

Ma = F - $F_{2}$

force exerted by the lighter block on the heavier block is calculated as

$F_{2}$ = F - Ma

$F_{2}$ = 80 - (11 x 6.67)

$F_{2}$ = 6.63 N

8 0

3 years ago

Sobre un recipiente lleno de agua se sumerge completamente un objeto que desplaza un volumen de 0.096 metros cúbicos de agua hac

Licemer1 [7]

Answer:

Fb = 941.76 [N]

Explanation:

La fuerza de flotacion se define como el producto de la densidad del liquido por la aceleración gravitacional y por el volumen desplazado

Fb = Ro*g*V

donde:

Fb = fuerza de flotacion [N] (unidades del Newtons)

Ro = densidad del liquido = 1000 [kg/m³]

g = aceleracion gravitacional = 9.81 [m/s²]

V = volumen desplazado = 0.096 [m³]

Reemplazando:

Fb = 1000*9.81*0.096

Fb = 941.76 [N]

7 0

3 years ago