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3 years ago

Stereotypes are widely held beliefs that people have certain traits because

Physics

1 answer:

Ray Of Light [21]3 years ago

4 0

Answer:

Stereotypes are widely held beliefs that people have certain traits because they belong to a particular group stereotypes are often in accurate and frequently portray the members of less powerful less controlling groups or negatively and members of more powerful more controlling groups.

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Which is an important step in how an electric motor uses magnetic force to produce motion?

Romashka [77]

The basic idea of an electric motor is really simple: you put electricity into it at one end and an axle (metal rod) rotates at the other end giving you the power to drive a machine of some kind. Hope this helps. Have a nice day. Feel free to ask more questions.

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3 years ago

Read 2 more answers

A peregrine falcon dives at a pigeon. The falcon starts downward from rest with free-fall acceleration. If the pigeon is 56.0 m

goldenfox [79]

The solution would be like this for this specific problem:

v = ? 
u = 0.0 m/s 
a = 9.8 m/s^2 
s = 56.1 m

v^2 = (0.0 m/s)^2 + [2 * (9.8 m/s^2) * (56 m) ] 
v^2 = 2 * (9.8 m/s^2) * (56 m) 
v^2 = 1,097.6 m^2/s^2 
v = SQRT {1,097.6 m^2/s^2 }

v = 33.1 m/s

v = u + at

(v - u) / a = t

[ (33.1 m/s) - (0.0 m/s) ] / (9.8 m/s^2) = 3.38 seconds

If the pigeon is 56.0 m below the initial position of the falcon, it will take 3.38 seconds for the falcon to reach the pigeon. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

4 0

3 years ago

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A car pulled by a tow truck has an acceleration of 2.0 m/s^2. What is the mass of the car if the net force on the car is 3,500 N

Nana76 [90]

Answer:

ans: 1750 kg

Explanation:

F = ma

so ,

m = F/a

= 3500 / 2

= 1750 kg

5 0

3 years ago

If the force that propels the cannonball forward is 500N, how much force will move the cannon backward?

Licemer1 [7]

Answer:

Well it would be equal to 500N because pushing forward the ball (or whatever maybe a body) would push the canon back an even 500N backwards...

Explanation:

6 0

3 years ago

A 2.7-kg block is released from rest and allowed to slide down a frictionless surface and into a spring. The far end of the spri

exis [7]

a) The speed of the block at a height of 0.25 m is 2.38 m/s

b) The compression of the spring is 0.25 m

c) The final height of the block is 0.54 m

Explanation:

We can solve the problem by using the law of conservation of energy. In fact, the total mechanical energy (sum of kinetic+gravitational potential energy) must be conserved in absence of friction. So we can write:

$U_i +K_i = U_f + K_f$

where

$U_i$ is the initial potential energy, at the top

$K_i$ is the initial kinetic energy, at the top

$U_f$ is the final potential energy, at halfway

$K_f$ is the final kinetic energy, at halfway

The equation can be rewritten as

$mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2$

where:

m = 2.7 kg is the mass of the block

$g=9.8 m/s^2$ is the acceleration of gravity

$h_i = 0.54$ is the initial height

u = 0 is the initial speed

$h_f = 0.25 m$ is the final height of the block

v is the final speed when the block is at a height of 0.25 m

Solving for v,

$v=\sqrt{u^2+2g(h_i-h_f)}=\sqrt{0+2(9.8)(0.54-0.25)}=2.38 m/s$

The total mechanical energy of the block can be calculated from the initial conditions, and it is

$E=K_i + U_i = 0 + mgh_i = (2.7)(9.8)(0.54)=14.3 J$

At the bottom of the ramp, the gravitational potential energy has become zero (because the final heigth is zero), and all the energy has been converted into kinetic energy. However, then the block compresses the spring, and the maximum compression of the spring occurs when the block stops: at that moment, all the energy of the block has been converted into elastic potential energy of the spring. So we can write

$E=E_e = \frac{1}{2}kx^2$

where

k = 453 N/m is the spring constant

x is the compression of the spring

And solving for x, we find

$x=\sqrt{\frac{2E}{k}}=\sqrt{\frac{2(14.3)}{453}}=0.25 m$

If there is no friction acting on the block, we can apply again the law of conservation of energy. This time, the initial energy is the elastic potential energy stored in the spring:

$E=E_e = 14.3 J$