The characteristics of the velocity vector used to find the results for the direction of acceleration and velocity are:
- Acceleration is towards the center of the circle
- The velocity is tangent to the circle counterclockwise.
Newton's Second Law establishes a relationship between force, mass and acceleration of bodies.
<h3>Centripetal acceleration.
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In the case of circular motion there is a constant change in the direction of the velocity vector, even when its module remains constant, this change in direction points towards the center of the circle, so that the module is constant.
They indicate that the satellite is moving counterclockwise, therefore the speed must go to the left (counterclockwise) tangential to the circle.
In conclusion using the characteristics of the velocity vector we can find the results for the direction of acceleration and velocity are:
- Acceleration is towards the center of the circle
- The velocity is tangent to the circle counterclockwise.
Learn more about centripetal acceleration here: brainly.com/question/25243603
Answer:
Mass = 64,870,000,000 kilograms
Explanation:
Given the following data;
Density = 998 kg/m³
Volume = 6,500,000 m³
To find the mass of water in the reservoir;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
Density = mass/volume
Making mass the subject of formula, we have;
Mass = density * volume
Mass = 998 * 6,500,000
Mass = 64,870,000,000 kilograms
Answer:

Explanation:
Given


Required
Determine the speed of the jet
The speed is calculated as:

Substitute 4800 km for Distance and 6hr for Time


<em>Hence, the speed of the commercial jet is 800km/hr</em>
Answer:
a) t = 0.528 s
b) D = 1.62 m
Explanation:
given,
speed of the baseball = 3.75 m/s
angle made with the horizontal = 35°
height of the roof edge = 2.5 m
using equation of motion



4.9 t² + 2.15 t - 2.5 = 0
on solving the above equation
t = 0.528 s
b) D = v cos θ × t
D = 3.75 × cos 35° ×0.528
D = 1.62 m