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Volgvan
4 years ago
11

What occurs along a convergent plate?

Physics
1 answer:
Tasya [4]4 years ago
3 0
Your answer is D. Earthquakes and hot spots occur along convergent plates. 
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If you were to stir salt in water until the salt disappeared, which is the solute?
emmainna [20.7K]
Salt is the solute in that situation

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3 years ago
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Answer the following questions for a mass that is hanging on a spring and oscillating up and down with simple harmonic motion. N
LiRa [457]

Answer:

1. equilibrium

2. bottom

3. bottom

4. nowhere

5. bottom

6. top & bottom

7. equilibrium

8. equilibrium

1. No

2. Yes

Explanation:

According to the following equation of motion for SHM:

x(t) = A\cos(\omega t + \phi)

where A is the amplitude, ω is the angular frequency, and ∅ is the phase angle.

Furthermore, the velocity and acceleration functions are as follows:

y(t) = -\omega A\sin(\omega t + \phi)\\a(t) = -\omega^2 A\cos(\omega t + \phi)

1. The acceleration is zero at the equilibrium. At the equilibrium, the net force on the object is zero. And according to Newton's Second Law, if the net force is zero, then the acceleration is zero as well.

2. The forces on the object in a vertical spring are the weight of the object and the spring force.

F = mg - kx

Since mg is constant along the motion, then the net force is maximum at the amplitude. For the special case in this question, the mass is always below the rest length of the spring. So the net force is maximum at the lower amplitude, because x is greater in magnitude at the lower amplitude.  According to Newton's Second Law, acceleration is proportional to the net force, hence the acceleration is at a maximum at the bottom.

3. As explained above, the magnitude of the net force is at a maximum at the lower amplitude, that is bottom.

4. The spring force is defined by Hooke's Law: F = -kx. Since the oscillation is small enough so that the mass is always below the rest length of the spring, then x is always greater than zero, hence nowhere in the motion will the spring force becomes zero.

5. As explained above, the force of gravity is constant and the spring force is proportional to the displacement, x. Therefore, the spring force is at a maximum at the lower amplitude, that is bottom.

6. The speed is zero when the mass is instantaneously at rest, that is the amplitude.

7. The net force on the mass is zero at the equilibrium.

8. The speed is at a maximum at the equilibrium.

1.  We will use the equation of motions given above. For simplicity, let's take ∅ = 0. At half its amplitude:

\frac{A}{2} = A\cos(\omega t)\\\frac{1}{2} = \cos(\omega t)\\\omega t = \pi / 3

Then the velocity at that point is

v(t) = -\omega A\sin(\pi /3) = -\omega A (0.866)

The maximum speed is where the acceleration is equal to zero:

0 = -\omega^2 A\cos(\omega t)\\\omega t = \pi / 2\\v_{max} = -\omega A\sin(\pi /2) = -\omega A

Comparing the maximum velocity to the velocity at A/2 yields that it is not half the maximum velocity:

-\omega A(0.866) \neq -\omega A

2. The maximum acceleration is at the amplitude.

A = A\cos(\omega t)\\\omega t = 2\pi\\a_{max} = -\omega^2 A\cos(2\pi) = -\omega^2 A

And the acceleration at A/2 is

\frac{A}{2} = A\cos(\omega t)\\\omega t = \pi / 3\\a(t) = -\omega^2 A\cos(\pi / 3) = -\omega^2 A (0.5)

Comparing these two results yields that the acceleration at half the amplitude is half the maximum acceleration.

5 0
3 years ago
Acceleration is directly proportional to the applied force and inversely proportional to the object's mass." Which formula corre
dolphi86 [110]

Answer:

a=m/f

Explanation:

ifkvmfkb gjbn trkbv mrgvbmnrgvngkbngjbntguj

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3 years ago
Starting from rest, a 75.0-kg snowboarder slides straight down a 115-m slope in 6.6 s. If the slope is a 35°
Likurg_2 [28]

The acceleration of the snowboarder is 5.6 m/s^2 down along the incline

Explanation:

To find the acceleration of the snowboard, we have to analyze the forces acting along the direction parallel to the incline.

There is only one force acting in this direction, and it is the component of the weight parallel to the incline, given by

mg sin \theta

where

m = 75.0 kg is the mass of the man

g=9.8 m/s^2 is the acceleration of gravity

\theta=35^{\circ} is the angle of the incline

Substituting, we find that the net force along the incline is:

F=(75.0)(9.8)(sin 35^{\circ})=421.6 N

According to Newton's second law, the net force on the snowboard is equal to the product between his mass and his acceleration:

F=ma

where a is the acceleration. Therefore, solving for a, we find

a=\frac{F}{m}=\frac{421.6}{75}=5.6 m/s^2

And the direction of this acceleration is down along the incline.

Learn more about acceleration and Newton's second law:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

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3 years ago
Physical property of Aluminum foil can be gray color
bixtya [17]
Solid, Malleable, and it reflects light and heat. Those are (some) physical properties.
3 0
3 years ago
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