Answer:
Explanation:
Given
Initial speed of ball 
Launch angle 
As there is no acceleration in horizontal direction therefore there is no change in velocity
thus horizontal velocity remains unchanged



Time of flight of projectile is



Thus time for which it is in air is 2.12 s
I just now did it and it said your answer was actually wrong the real answer is 0.84
Answer:
horizontal component=fcostita
=150cos60
use calculator to evaluate it
for vertical=fsintita
=150sin60