Answer:
the frequency heard by the observer is equal to 2677 Hz
Explanation:
given,
velocity of the observer = 17 m/s
speed of the sound = 343 m/s
velocity of the source = 0 m/s
frequency emitted from the source = 2550 Hz
velocity of observer is negative as it is approaching the source. f = 2676.38 Hz ≈ 2677 Hz
hence, the frequency heard by the observer is equal to 2677 Hz
The position of the particle is given by:
x(t) = t³ - 12t² + 21t - 9
Differentiate x(t) with respect to t to find the velocity x'(t):
x'(t) = 3t² - 24t + 21
Differentiate x'(t) with respect to t to find the acceleration x''(t):
x''(t) = 6t - 24
There may be an improper voltage in the device.
<u>Explanation</u>:
- Given the device has unknown circuitry and the voltage across the device crosses the voltage across the resistor at 500 Hz. In this device, the current flow is not correct. It is improper.
- The elements in the device are ammeter, capacitor, inductor, voltmeter, and battery. The components in the device may not be connected properly. This is due to the improper flow of current and condition of the voltmeter.
- So these are the type of elements in the device.
The proof that the earth is rotating is the happens of night and day also the seasons, eg. winter, summer, autumn.
