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Len [333]
4 years ago
11

A slab of glass has a 0.600 cm thick layer of water on top of it. A light ray strikes the water at an incident angle of 59.0°. A

t what angle does the light ray travel through the glass?
Physics
1 answer:
Dimas [21]4 years ago
4 0

Answer:

49.63 degree

Explanation:

thickness of glass slab, t = 0.6 cm

angle of incidence = 59 degree

Let r be the angle of refraction

The refractive index of glass, ng = 3/2

refractive index of water, nw = 4/3

refarctive index of glass with respect to water = ng / nw = 3 /2 ÷ 4 /3 = 9 / 8

So, by use of Snell's law

Refractive index of glass with respect to water = Sin i / Sin r

9 / 8 = Sin 59 / Sin r

9 / 8 = 0.857 / Sin r

Sin r = 0.7619

r = 49.63 degree

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This answer is fluorine
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What is the wavelength of a wave?
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I know for a fact the answer is D. the distance traveled by the wave during one full cycle
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The tires of a car support the weight of a stationary car. If one tire has a slow leak, the air pressure within the tire will __
Kipish [7]

Answer:

The tires of a car support the weight of a stationary car. If one tire has a slow leak, the air pressure within the tire will decrease with time, the surface area between the tire and the road will increase with time, and the net force the tire exerts on the road will be constant with time.

Explanation:

when a wheel has an air leak, it means that the inside of the tire has less air, which means that there will be less air pushing the walls of the tire so that the air pressure decreases.

On the other hand, the tire begins to deform due to lack of air which increases the area of ​​contact with the floor.

As the weight of the car remains constant and the air has a negligible mass the force towards the road will be the same

4 0
4 years ago
Calculate the number of moles of gas present in the sealed container at a
aliina [53]

Here volume of gas is not given so question is solved assuming volume as 1 L.

The number of moles of 1 L gas present in the sealed container at a

pressure of 125 kPa at 25 degrees Celsius is 0.0067 moles.

The ideal gas law equation can be written as

PV  = nR T

Here

P is the pressure of the gas in atm

V is the volume it occupies in L

n is the number of moles of gas present in the sample

R is the universal gas constant, equal to 0.0821 atm L/ mol K

T is the absolute temperature of the gas in Kelvin

Now, it's important to realize that the units you have for the volume, pressure, and temperature of the gas must match the unit used in the expression of the universal gas constant.

So

P = 125 kPa

1 atm = 760 kPa

P = 125/760 = 0.1644 atm

T = 25 degree celsius  = 25 +273 = 298 K

Taking V  = 1 L

So

n  = PV/RT

n = 0.1644 x 1 / 0.0821 x 298

n =  0.0067 moles

To learn more about the ideal gas law, please click on the link brainly.com/question/128737528

#SPJ9

8 0
2 years ago
In a double-slit experiment, the third-order maximum for light of wavelength 490 nm is located 15 mm from the central bright spo
jeka94

Answer:

The distance from the central bright spot are 156.8\times10^{-3}\ mm and 142.9\times10^{-3}\ mm.

Explanation:

Given that,

Wavelength = 490 nm

Distance y= 15 mm

Length L=1.6 m

New wavelength = 670

We need to calculate the distance from the central bright spot

Using formula of distance

y= \dfrac{m\lambda L}{d}

d=\dfrac{m\lambda L}{y}

Put the value into the formula

d=\dfrac{3\times490\times10^{-9}\times1.6}{15\times10^{-3}}

d=156.8\times10^{-6}\ m

d=156.8\times10^{-3}\ mm

We need to calculate the distance from the central bright spot for new wavelength

Using formula of distance

d=\dfrac{m\lambda L}{y}

Put the value into the formula

d=\dfrac{2\times670\times10^{-9}\times1.6}{15\times10^{-3}}

d=142.9\times10^{-6} m

d=142.9\times10^{-3}\ mm

Hence, The distance from the central bright spot are 156.8\times10^{-3}\ mm and 142.9\times10^{-3}\ mm.

8 0
3 years ago
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