Ask question

Ask question

All categories

3 years ago

13

a cookie recipe calls for a half cup of chocolate chips per 3 dozen cookies. How many cups of chocolate chips should be used for

10 dozen cookies?

1 answer:

Dahasolnce [82]3 years ago

3 0

To answer this question, you should set up a proportion that demonstrates the ratio of chocolate chips to cookies.

$\frac{0.5}{36} =\frac{x}{120}$

36 and 120 are used because 1 dozen=12.

Cross multiply and solve for x to get the answer.

$60=36y$

$\frac{5}{3}=x$

The answer is $\frac{5}{3}$ cups.

You might be interested in

I need to know how to make the equations

Bogdan [553]

Asked and answered elsewhere.
brainly.com/question/9016540

3 0

3 years ago

Calcula el volumen en metros cúbicos de una piscina que tiene 8 m de largo 2 m de ancho y 1.5 m de profundidad

Stella [2.4K]

Answer:

V = 24 m³

Step-by-step explanation:

The given question says that, 'Calculate the volume in cubic meters of a pool that is 8 m long, 2 m wide and 1.5 m deep'.

A pool is in the shape of a cubiod. The volume of the cuboid is given by :

V = lbh

Where

l is length, b is width and h is height

Put all the values,

V = 8 × 2 × 1.5

= 24 m³

So, the volume of the pool is equal to 24 m³.

7 0

3 years ago

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal plac

valentinak56 [21]

Answer:

tan(θ) = 0, 0.577, -0.577

Step-by-step explanation:

3tan³(θ) - tan(θ) = 0

tan(θ)(3tan²(θ) - 1) = 0

tan(θ) = 0

tan²(θ) = ⅓ tan(θ) = +/- sqrt(⅓)

tan(θ) = 0, sqrt(⅓), -sqrt(⅓)

tan(θ) = 0, 0.577, -0.577

To find θ values, domain is required

6 0

3 years ago

How many solutions does the equation 3x + 6 equals -1 - 3 + 4x have?

wariber [46]

3x + 6 = -1 - 3 + 4x
Combine like terms on the right side.

3x + 6 = -4 + 4x
Add 4 to both sides.

3x + 10 = 4x
Subtract 3x from both sides.

10 = x

The equation has one solution (10).

3 0

3 years ago

Read 2 more answers

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

2 years ago