Your question is not clear, but it looks as though you want to know how Brie can make a similar sandbox with base = 8ft.
Answer:
For Brie to make a similar sandbox, he must use a base = 8ft, and height = (8/3)ft
Step-by-step explanation:
It is possible for Brie to make a similar triangular sandbox with base = 12ft and height = 4ft.
All he must ensure is that the ratio of base to height of the original sandbox is the same ratio of base to height of the one he is trying to make.
The original sandbox is 12:4
Because he wants to use a base = 8ft, the sandbox he is trying to make is 8:x
Where x is the height of the sandbox he is trying to make.
Then for these sandboxes to be similar, the ratio 12:4 = 8:x
=> 12/4 = 8/x
12x = 8 × 4
12x = 32
x = 8/3
The height must be (8/3)ft
Answer:
MN = 160
Step-by-step explanation:
We know that arc MN = arc NO
17g - 10 = 14g+ 20
Subtract 14g from each side
3g -10 = 14g-14g+20
3g -10 =20
Add 10 to each side
3g = 20+10
3g = 30
Divide by 3
3g/3= 30/3
g= 10
We want the arc MN
17g - 10
17(10) - 10
170 -10
160
It takes Omar 30 seconds to eat one considering he ate 8 in 4 minutes ...
If we really wanted to we could turn this into the fraction 8/4
8 being the amount of carrot sticks he ate and 4 being the time it took
now all u have to do is simplify that turns into 2/1 and since the 1 is one minute and her can eat 2 in one minute we can safely say he eats 1 carrot stick every 30 seconds
:) hope this helps!!
If the width of the cardboard = x cm then its length is given by x + 8 cm.
Then the length of the box will be x + 8 - 2(2) = x + 4
and the width = x - 2(2) = x - 4 cm The height is 2 cm
Volume = h*w*l = 2(x - 4)(x + 4) = 256
2(x^2 - 16) = 256
x^2 - 16 = 128
x^2 = 144
x = 12 cm
Dimensions of the box are:-
length = 12 + 4 = 16cm
width = 12 - 4 = 8 cm
height = 2 cm
Answer:
Approximately 50 square feet (50.24 to be exact)
Step-by-step explanation:
If you're using 3.14 for π, and the area of a circle is A=πr2,
(3.14)(4)^2 =?
(3.14)(16) = 50.24
Therefore the answer would be about 50 square feet.
