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Aleks [24]
3 years ago
8

If two objects are the same size but one object is 3 times hotter than the other object, the hotter object emits If two objects

are the same size but one object is 3 times hotter than the other object, the hotter object emits 3 times more energy per time per area. 9 times more energy per time per area. 12 times more energy per time per area 81 times more energy per time per area. none of the above
Physics
1 answer:
Illusion [34]3 years ago
8 0

Answer:

81 times the first body

Explanation:

Let the temperature of the first object is T.

The temperature of the second object is 3T.

According to the Stefan's law, the energy radiated per unit area per unit time is given by

E \alpha T^{4}

So, for the first body

E_{1} \alpha T^{4}      .... (1)

for the second body

E_{2} \alpha (3T)^{4}    ..... (2)

By equation (1) and (2),

E2 = 81 times E1

So, the second body gives 81 times more energy per unit area per unit time

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oksian1 [2.3K]

Answer:

The shear stress at a distance 0.3-in away from the pipe wall is 0.06012lb/ft²

The shear stress at a distance 0.5-in away from the pipe wall is 0

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length of the pipe = 12 feet

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\frac{\delta P}{L} = \frac{2 \tau}{r} \\\\

make shear stress (τ) the subject of the formula

\frac{\delta P}{L} = \frac{2 \tau}{r} \\\\\tau = \frac{\delta P *r}{2L}

Where;

τ is the shear stress on the pipe wall.

ΔP is the pressure drop

L is the length of the pipe

r is the distance from the pipe wall

Part (a) shear stress at a distance of  0.3-in away from the pipe wall

Radius of the pipe = 0.5 -in

r = 0.5 - 0.3 = 0.2-in = 0.0167 ft

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\tau = \frac{\delta P *r}{2L}  = \frac{86.4 *0.0167}{2*12} =0.06012 \ lb/ft^2

Part (b) shear stress at a distance of  0.5-in away from the pipe wall

r = 0.5 - 0.5 = 0

\tau = \frac{\delta P *r}{2L}  = \frac{86.4 *0}{2*12} =0

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3 years ago
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